The mechanical efficiency = actual work / ideal work
So ζ = 1540 / 1600 * 100% = 96.25%
Find the electric flux and the disp at t=0.50ns
<span>Given: </span>
<span>Resistor R = 160 Ω </span>
<span>Voltage ε = 22.0 V </span>
<span>Capacitor C = 3.10 pF = 3.10 * 10^-12 F </span>
<span>time t = 0.5 ns = 0.5 * 10^-9 s </span>
<span>ε0 = 8.85 * 10^-12 </span>
<span>Solution: </span>
<span>ELECTRIC FLUX: </span>
<span>Φ = Q/ε0 </span>
<span>we have ε0, we need to find Q the charge </span>
<span>STEP 1: FIND Q </span>
<span>Q = C ε ( 1 - e^(-t/RC) ) </span>
<span>Q = { 3.10 * 10^-12 } { 22.0 } { 1 - e^(- 0.5 * 10^-9 / 160 *3.10 * 10^-12 ) } </span>
<span>Q = { 3.10 * 10^-12 } { 22.0 } { 1 - 0.365 } </span>
<span>Q = { 3.10 * 10^-12 } { 22.0 } { 0.635 } </span>
<span>Q = 43.31 * 10^-12 C </span>
<span>STEP 2: WE HAVE Q AND ε0 > >>> SOLVE FOR ELECTRIC FLUX >>> </span>
<span>Φ = Q/ε0 </span>
<span>Φ = { 43.31 * 10^-12 C } / { ε0 = 8.85 * 10^-12 } </span>
<span>Φ = 4.8937 = 4.9 V.m </span>
<span>DISPLACEMENT CURRENT </span>
<span>we use the following equation: </span>
<span>I = { ε / R } { e^(-t/RC) } </span>
<span>I = { 22 / 160 } { e^(- 0.5 * 10^-9 / 160 *3.10 * 10^-12 ) } </span>
<span>I = { 0.1375 } { 0.365 } </span>
<span>I = 0.0502 A = 0.05 A </span>
Answer:
Approximately 
.
Explanation:
The net force on the girl would be:
.
Under the assumptions, the net force on this girl would be equal to the tension force in the rope. All other forces on the girl would be balanced.
In other words, the tension force that the rope exerted on the girl would be 
. The girl would exert a reaction force on the rope at the same magnitude (
) in the opposite direction. This force would translate to a 
force on the boy towards the girl.
Under similar assumptions, the net force on the boy would also be . Since the mass of the boy is 
, the acceleration of the boy would be:
.
Since this is a horizontal path, we can neglect the force of gravity acting on the body. So in this case we have that the force of tension is equal to the centripetal force, because we have a circular path.
Fcp=T, where T is the force of tension and Fcp is the centripetal force.
m*(v²/R)=250 N, where m is the mass of the body and it is m=0.3 kg, v is the max speed of the body, and that is what we are looking for and R is the max length of the string and it is R=0.75 m.
We divide by m and multiply by R and we get:
v²=(250*R)/m, take the square root:
v=√((250*R)/m)=25 m/s
So the max speed of the body if the max tension is T= 250 N and its max length is R=0.75 m is V=25 m/s.
Answer:
B
Explanation:
This is a physics question, know that force is equals to mass divided by acceleration (acc.), so if the same force is applied, say 10 Newton and the mass of A is 2 and the mass of B is 4, then the acceleration of A is 0.2 and that of B is 0.4 by equating, and this applies to all cases.
