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3 years ago

A car travels 200km in 3.0 hours. Determine the average velocity of the car

Physics

1 answer:

Masja [62]3 years ago

4 0

Answer:

Explanation:

The average velocity of the car can be found by using the formula

$a = \frac{d}{t } \\$

d is the distance

t is the time taken

From the question we have

$a = \frac{200}{3} \\ = 66.66666...$

We have the final answer as

Hope this helps you

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A block of mass m sits at rest on a rough inclined ramp that makes an angle θ with the horizontal. What must be true about force

nignag [31]

Answer:

Option B

Explanation:

For a system of block on inclined ramp shown in the attached image. From the attached image, the Normal force N, weight mg and frictional force f act on the block. The sum of vertical forces should be zero just as sum of vertical forces should be zero when the system is in equilibrium condition.

Taking sum of forces along the inclined plane we deduce that

[tex]f=mgsin \theta [tex]

Therefore, option B is the correct option.

8 0

3 years ago

A laser beam of wavelength 600 nm is incident on two slits that are separated by 0.02 mm. What is the separation between adjacen

Liula [17]

Answer:

option D

Explanation:

given,

wavelength = 600 nm

width of separation = 0.02 mm

L = 5 m

for mth order maxima

$d \times \dfrac{y_m}{L}=m\lambda$

for (m+1)th order maxima

$d \times \dfrac{y_{m+1}}{L}=(m+1)\lambda$

now,

$y_m=\dfrac{mL\lambda}{d}$ and

$y_{m+1}=\dfrac{(m+1)L\lambda}{d}$

hence,

$\Delta y = y_{m+1} - y_m$

$\Delta y =\dfrac{L\lambda}{d}$

$\Delta y =\dfrac{5 \times 600 \times 10^{-9}}{0.02 \times 10^{-3}}$

$\Delta y =0.15\ m$

$\Delta y =15\ cm$

hence, the correct answer is option D

4 0

4 years ago

A car moving at 18 m/s decelerates at -- 2.5 m/s" as it approaches a stop sign.

yulyashka [42]

Answer:

equation: Vf=Vo - at

t= (Vf- Vo)/a

t=(0m/s - 18m/s)/(-2.5m/s²)

t= 7.2 s

7 0

4 years ago

Read 2 more answers

ich of the following is not accurate when describing solids? A. The amount of pressure exerted by a solid is solely dependent on

Dafna11 [192]

The amount of solid does not affect how you are describing the solid so a is the answer

5 0

3 years ago

Rank the angular speed of the following objects, from highest to lowest:- A bowling ball of radius 12.3 cm rotating at 8.21 radi

dlinn [17]

Answer:

A bowling ball (8.21rad/s) > A tire (7.94rad/s) > A square (7.75rad/s) > A rock (6.98rad/s) > A top spinning (6.54rad/s)

Explanation:

<u>To rank the angular speed (ω) of the objects, we need first calculate its value for every object:</u>

A bowling ball of radius 12.3cm rotating at 8.21 radians per second:

ω = 8.21 rad/s

A tire of radius 0.321m rotating at 75.8 rpm:

$\omega = 75.8 \frac{rev}{min}\cdot \frac{2\pi rad}{1rev}\cdot \frac{1min}{60s} = 7.94rad/s$

A 6.84cm diameter top spinning at 375 degrees per second:

$\omega = 375 \frac{^\circ}{s}\cdot \frac{2\pi rad}{360^ \circ} = 6.54rad/s$

A square with sides (b) 0.458m long, whose corners are moving with tangential speed (v) 2.51 m/s as it rotates about its center:

$\omega = \frac{v}{r} = \frac{v}{\frac{b}{2}\sqrt 2} = \frac{2.51 m/s}{\frac{0.458 m}{2} \sqrt 2} = 7.75rad/s$

A rock on a string, being swung in a circle of radius 0.521 m with a centripetal acceleration (a) of 25.4 m/s²:

$\omega = \sqrt \frac{a}{r} = \sqrt \frac{25.4 m/s^{2}}{0.521m} = 6.98rad/s$

<u>Now, the rank of the angular speed of the objects, from highest to lowest is: </u>

A bowling ball (8.21rad/s) > A tire (7.94rad/s) > A square (7.75rad/s) > A rock (6.98rad/s) > A top spinning (6.54rad/s)

I hope it helps you!

4 0

3 years ago