Answer:
Options A, B as well as C are the correct choices.
Explanation:
- Collaborative learning seems to be a circumstance where learning is an educational approach as well as make an effort to understand all this together.
- Except for personal learning, people participating in this learning draw mostly on competencies and qualifications of each other.
This form of learning isn't always linked to the perhaps one given choice. And the response to the above will still be the appropriate one.
<span>There is no special name for that. Physics is usually just concerned with "forces", and doesn't specify whether the force pushes or pulls. If you want to be more specific, you can just call it a "pulling force".
I hoped this was satisfying!:)</span>
The three main cycles of an ecosystem are the water cycle, the carbon cycle and the nitrogen cycle.
Answer:
a) F = -1035.385 N
b) Backwards
c) s = 15.60 m
Explanation:
Given information
= Initial Speed of Car = 15.0 m/s
= Final Speed of Car = 9.00 m/s
= Breaking Time = 1.30 s
= Mass of Car = 1040 kg
Part (a)
To find the force exerted on the car we use the following formula
Where
= Force = unknown
= Mass of Car = 1040 kg
= Acceleration of Car / Deceleration of Car = unknown
To find the force (F) we need to first find the deceleration rate (a)
To find the deceleration rate we use the following formula
Inputting the given values
To find the force
Part (b)
Since the value of F is negative this means the the force was opposite the direction of motion, hence the force was backwards.
Part (c)
To find the total distance the car moved while braking we use the following formula
Where
= distance traveled
Inputting the values given
Answer:
a. the time required for the onset of evaporation is: 196.1 seconds and b. the time required for all of the water to evaporate is: 1328.3 seconds.
Explanation:
We need to stablish that there is 3 states at this problem. At the firts one, water is compressed liquid and the conditions for this state are: P1=100KPa,T1=20°C,V1=0.5m^3. From the compressed liquid chart and using extrapolation, we can get: v1=vf1=0.0010018 (m^3/Kg) and u1=uf1=83.95(KJ/kg). Now we can find the mass of water at the state 1 as: 
Then the liquid water is heated at a rate of 0.85KW, and its volume increase, while work is done by the system at the boundary, we can assume that the pressure remains constant throughout the entire process. At the second state the water is saturated liquid and the conditions are: P2=100KPa, T2=Tsat=99.63°C, v2=vf2=0.001043(m^3/Kg) and u2=uf2=417.36(KJ/Kg). Now we can find the work as:
. (a) After that we need to do an energy balance for process 1-2 and get: U=Q-W or 
, solving for t we get the time required for the onset of evaporation:
.(b) Then continue heat transfer to the cooking pot and results in phase change getting vapor at 99.63°C. At the final state or third state the mass is zero because all liquid was evaporated and the initial mass at this state is the same for the second state: 0.5 (Kg) and doing an energy balances results in:
, but m3=0, now solving for t we can get the time required for all of the water to evaporate as:
. We can get from the saturated liquid chart the enthalpy he=hge=2675.5(KJ/Kg) @P=100KPa. Now we need to calculate the work related with the volume decreases as vapor exits the control volume or process 2-3 work boundary as: 
. Now replacing every value in the time equation we get:
