5x^2-6x-3=0<br> x=<br> x=<br> plz help

Find the annual interest rate. Round your answer to the nearest hundredth of a percent. I=$160.67, P=$2000, t=8 monthsI=$160.67,

Keith_Richards [23]

Answer:

The annual interest rate is 12.05%.

Step-by-step explanation:

The simple interest is given by the formula:

$I=\dfrac{P\times R\times T}{100}$

Where I denotes interest.

P denotes the principal amount.

R denotes the rate of interest

and T denotes the time period.

I=$160.67, P=$2000, t=8 months=8/12 years (Since 12 months=1 year so 1 month=1/12 year)

$160.67=\dfrac{2000\times R \times \dfrac{8}{12}}{100}\\\\R=12.05%$

Hence, the annual interest rate is 12.05%.

5 0

4 years ago

Read 2 more answers

A small rocket is fired from a launch pad 10 m above the ground with an initial velocity left angle 250 comma 450 comma 500 righ

jonny [76]

Let $\vec r(t),\vec v(t),\vec a(t)$ denote the rocket's position, velocity, and acceleration vectors at time $t$ .

We're given its initial position

$\vec r(0)=\langle0,0,10\rangle\,\mathrm m$

and velocity

$\vec v(0)=\langle250,450,500\rangle\dfrac{\rm m}{\rm s}$

Immediately after launch, the rocket is subject to gravity, so its acceleration is

$\vec a(t)=\langle0,2.5,-g\rangle\dfrac{\rm m}{\mathrm s^2}$

where $g=9.8\frac{\rm m}{\mathrm s^2}$ .

a. We can obtain the velocity and position vectors by respectively integrating the acceleration and velocity functions. By the fundamental theorem of calculus,

$\vec v(t)=\left(\vec v(0)+\displaystyle\int_0^t\vec a(u)\,\mathrm du\right)\dfrac{\rm m}{\rm s}$

$\vec v(t)=\left(\langle250,450,500\rangle+\langle0,2.5u,-gu\rangle\bigg|_0^t\right)\dfrac{\rm m}{\rm s}$

(the integral of 0 is a constant, but it ultimately doesn't matter in this case)

$\boxed{\vec v(t)=\langle250,450+2.5t,500-gt\rangle\dfrac{\rm m}{\rm s}}$

and

$\vec r(t)=\left(\vec r(0)+\displaystyle\int_0^t\vec v(u)\,\mathrm du\right)\,\rm m$

$\vec r(t)=\left(\langle0,0,10\rangle+\left\langle250u,450u+1.25u^2,500u-\dfrac g2u^2\right\rangle\bigg|_0^t\right)\,\rm m$

$\boxed{\vec r(t)=\left\langle250t,450t+1.25t^2,10+500t-\dfrac g2t^2\right\rangle\,\rm m}$

b. The rocket stays in the air for as long as it takes until $z=0$ , where $z$ is the $z$ -component of the position vector.

$10+500t-\dfrac g2t^2=0\implies t\approx102\,\rm s$

The range of the rocket is the distance between the rocket's final position and the origin (0, 0, 0):

$\boxed{\|\vec r(102\,\mathrm s)\|\approx64,233\,\rm m}$

c. The rocket reaches its maximum height when its vertical velocity (the $z$ -component) is 0, at which point we have

$-\left(500\dfrac{\rm m}{\rm s}\right)^2=-2g(z_{\rm max}-10\,\mathrm m)$

$\implies\boxed{z_{\rm max}=125,010\,\rm m}$

7 0

3 years ago

How many 3/4s are in 3 2/4

MArishka [77]

Answer:

the answer is 3

Step-by-step explanation:

First change the whole number (3) to quaters or fraction

3x $\frac{4}{4}$ = $\frac{12}{4}$

Now, add

$\frac{2}{4}$ + $\frac{12}{4}$ = $\frac{14}{4}$ Since, we have the same common denominator

now divide

14÷4 =3.5 = 3 $\frac{2}{4}$

Therefore, there are 3 of 3/4 with a remainder of $\frac{2}{4}$ in 3 $\frac{2}{4}$ .

7 0

3 years ago

Please help!!!

noname [10]

Answer:

Just be yourself. Also, in most cases, it's helpful to just let the boy come to you. If he comes to you and says he likes you, you should also express your own feelings. ALWAYS be yourself. If you aren't yourself, the relationship will not work out. The boy should like you for who you are, not who you're trying or pretending to be.

4 0

3 years ago

Read 2 more answers

Select the postulate that is illustrated for the real numbers.

jeka57 [31]

The answer would be 1. The commutative postulate for multiplication. Hope this helped! Good luck! :)

6 0

3 years ago

Read 2 more answers

5x^2-6x-3=0 x= x= plz help