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2 years ago

Pleasee help me with this i’m being timed

Mathematics

1 answer:

sammy [17]2 years ago

4 0

Answer:

I think she is correct

Step-by-step explanation:

in not. sure so dont take my word for it

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A sofa with an original price of $600 is put on sale for $480.

mario62 [17]

20% is the amount takin off of the sofa

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3 years ago

Read 2 more answers

1\ solve the system using elimination. 4x+5y=2 -2x+2y=8

il63 [147K]

The answer would be 6x+3y=2

6 0

3 years ago

Thrush us a landscape architect. For his first public project he is asked a small scale drawing of a garden to be placed in the

ehidna [41]

Answer:

Therefore, on the graph;

The height = 7.5 units

And base = 5.0 units

Attached is an image for further information;

Step-by-step explanation:

Given that;

1 unit on the grid represent 2m of the garden;

Ratio = 1/2 unit/m

For the height;

height h = 15m

On the graph;

h = 15m × 1/2 unit/m

h = 7.5 units

For the base;

Base b = 10m

On the graph;

b = 10m × 1/2 unit/m

b = 5 units

Therefore, on the graph;

The height = 7.5 units

And base = 5.0 units

6 0

3 years ago

A rectangular parking lot has a perimeter of 232 feet. the length of the parking lot is 36 feet less then the width. find the le

Troyanec [42]

Answer:

Length: 40 Width: 76

Step-by-step explanation:

W is width, and L is length.

We know that the length is 36 less than the width, so L = w - 36. Two times the width plus two times the length equals the perimeter, so set up the equation for the perimeter as:

232 = 2w + 2(w-36)

Now solve for w:

232 = 2w + 2w - 72

304 = 4w

w = 76

we now know that the width is 76, so solve for the length:

L= 76-36

L = 40

7 0

3 years ago

Harmonic mean if a number h such that (h-a)/(b-h)=a/b Prove h is H(a,b) iff satisfies either relation a. (1/a)-(1/h) = (1/h) - (

Fudgin [204]

A.

$\displaystyle\frac1a-\frac1h=\frac1h-\frac1b$
$\implies\displaystyle\frac{h-a}{ah}=\frac{b-h}{bh}$
$\implies\displaystyle\frac{h-a}{b-h}=\frac{ah}{bh}$
$\implies\displaystyle\frac{h-a}{b-h}=\frac ab$

b.

$\displaystyle h=\frac{2ab}{a+b}$
$\displaystyle\implies\frac{h-a}{b-h}=\frac{\frac{2ab}{a+b}-a}{b-\frac{2ab}{a+b}}$
$\displaystyle\implies\frac{h-a}{b-h}=\frac{2ab-a(a+b)}{b(a+b)-2ab}$
$\displaystyle\implies\frac{h-a}{b-h}=\frac{ab-a^2}{b^2-ab}$
$\displaystyle\implies\frac{h-a}{b-h}=\frac{a(b-a)}{b(b-a)}$
$\displaystyle\implies\frac{h-a}{b-h}=\frac ab$

The other direction can be proved by following the manipulations in the reverse order.

7 0

3 years ago