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3 years ago

10

What is the square root of -1?

2 answers:

solmaris [256]3 years ago

5 0

Answer:

Nill, there is no square root for negative figures

Step-by-step explanation:

Getting the square root of a negative figure is impossible. Only Positive integers and positive fractions can be manipulated to get their square root.

Anyways, the square of -1 is calculated as follows.

$-1^{2}$ =

-1 x -1 = 1

Alchen [17]3 years ago

4 0

Answer: √−1=i.

Step-by-step explanation: When we say that the square root of a negative number "doesn't exist", we mean that there is no real number solution. However, if we consider complex numbers, we then get a solution to √−1=i.

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Can I please get some help

Nitella [24]

Answer:

$f(3) = 3\\g(2) = -3\\g(\frac{1}{2}) = 1\\f(2) = \frac{2}{3}\\g(-2) = 0\\f(\pi) = 2\\$

Step-by-step explanation:

The functions are given f and g using coordinates.

Whenever we will ask for f(a), we look for "a" in the x coordinate of the function f and find the corresponding value. THAT IS THE ANSWER.

If we ask for g(b), we look for "b" in the x coordinate of the function g and find the corresponding value. THAT IS THE ANSWER.

So,

$f(3) = 3\\g(2) = -3\\g(\frac{1}{2}) = 1\\f(2) = \frac{2}{3}\\g(-2) = 0\\f(\pi) = 2\\$

5 0

4 years ago

What is the area of the triangle below? <br> 8 in.<br> 17 in.

zmey [24]

Answer:

68

Step-by-step explanation:

6 0

3 years ago

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What is the length of the diagonal of the square shown below?

Tatiana [17]

Answer:

sqrt(50)

Step-by-step explanation:

Since it is a right triangle, we can apply the Pythagorem Theorem.

a^2 + b^2 = c^2

25 + 25 = c^2

50 = c^2

c = sqrt(50)

6 0

3 years ago

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If you could help it'd mean the world to me

juin [17]

Answer: 22

Step-by-step explanation: because if you read it carefully and do math you are sure to get it right!! :)

3 0

3 years ago

Pre-image point N(6, -3) was dilated to point N'(2, -1). What was the scale factor used?

blagie [28]

Question 1

Let the scale factor be k.

Then, we have the mapping

$N(6,-3)\to N'(6k,-3k)$

This implies that:

$(6k,-3k)=(2,-1)$

We equate any corresponding component find the value of the scale factor k.

6k=2

$k=\frac{2}{6}$

$k=\frac{1}{3}$

Hence the scale factor is $\frac{1}{3}$

Question 2:

The midpoint of any two points can be calculated using the formula;

$(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})$

We want to find the midpoint of (-8, 5) and (2, -2).

$(\frac{-8+2}{2}, \frac{5+-2}{2})$

$(\frac{-6}{2}, \frac{3}{2})$

The midpoint is:

$(-3, \frac{3}{2})$

5 0

3 years ago

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