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bonufazy [111]
3 years ago
8

Which of the following variables would you need in order to calculate how long it would take a horizontally launched projectile

to hit the ground?
Physics
1 answer:
Scrat [10]3 years ago
4 0
I’m sorry but I’m going to need a picture.
You might be interested in
What type of relationship is shown in the graph
fenix001 [56]

Answer:

A linear, positive relationship

Explanation:

The graph is a line, so it is linear and the slope is positive, so it is positive...

6 0
3 years ago
an athlete runs 300 m up a hill at a steady speed of 3.0 m/s. She then immediately runs the same distance at 6.0 m/s . What is h
mina [271]

Answer:

4.0 m/s

Explanation:

In the first part of the run, the athlete runs a distance of

d_1 = 300 m

at a speed of

v_1 = 3.0 m/s

So, the time he/she takes is

t_1 = \frac{d_1}{v_1}=\frac{300}{3.0}=100 s

In the second part of the run, the athlete covers an additional distance of

d_2 = 300 m

with a speed

v_2 = 6.0 m/s

So, the time taken in this second part is

t_2 = \frac{d_2}{v_2}=\frac{300}{6.0}=50 s

So, the total distance covered is

d = 300 m + 300 m = 600 m

And the total time taken

t = 100 s + 50 s = 150 s

Therefore, the average speed for the entire trip is

v=\frac{d}{t}=\frac{600}{150}=4.0 m/s

4 0
4 years ago
A 2-kg bowling ball rolls at a speed of 10 m/s on the ground.
liberstina [14]
It's kinetic energy as the ball the ball isn't raised above the ground it does not have any gravitational potential energy. 
To find the kinetic energy of the ball you will have to use the formula:
KE=0.5 x m x v squared
m being mass and v being velocity 
so the calculation is:
0.5 x 2 x 10 x 10= 100J
8 0
4 years ago
A marching band is practicing. The band director sees the drum major hit a drum. How far away is the director if he hears the dr
ivanzaharov [21]

Answer:

825 m

Explanation:

330 m/s

1 / 0.40 = 2.5

330 x 2.5 = 825

7 0
3 years ago
A 10kg object experiences a horizontal force which causes it to accelerate 5 m/s2 moving it a distance of 20 m horizontally. How
mr_godi [17]

Answer:

The work done by the force is 1000 J.

Explanation:

Given:

Mass of object (m) = 10 kg

Acceleration of the object (a) = 5 m/s²

Displacement of the object (S) = 20 m

Using Newton's second law, we have:

Force = Mass × Acceleration

F=ma

Plug in the given values and solve for force 'F' acting on the object. This gives,

F=(10\ kg)(5\ m/s^2)\\\\F=50\ N

Now, work done by the force 'F' is equal to the product of force 'F' and the displacement it cause in its direction which is 20 m.

Therefore, the work done by the force is given as:

Work = Force × Displacement

W=FS

Plug in the values given and solve for 'W'. This gives,

W=50\ N\times 20\ m \\\\W=1000\ J

Therefore, the work done by the force is 1000 J.

7 0
4 years ago
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