Question

A 10kg object experiences a horizontal force which causes it to accelerate 5 m/s2 moving it a distance of 20 m horizontally. How much work is done by the force

Answer 1

Answer:

The work done by the force is 1000 J.

Explanation:

Given:

Mass of object (m) = 10 kg

Acceleration of the object (a) = 5 m/s²

Displacement of the object (S) = 20 m

Using Newton's second law, we have:

Force = Mass × Acceleration

$F=ma$

Plug in the given values and solve for force 'F' acting on the object. This gives,

$F=(10\ kg)(5\ m/s^2)\\\\F=50\ N$

Now, work done by the force 'F' is equal to the product of force 'F' and the displacement it cause in its direction which is 20 m.

Therefore, the work done by the force is given as:

Work = Force × Displacement

$W=FS$

Plug in the values given and solve for 'W'. This gives,

$W=50\ N\times 20\ m \\\\W=1000\ J$

Therefore, the work done by the force is 1000 J.