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4 years ago

What's is the difference between relative abundance vs percent abundance

1 answer:

6 0

Relative means you take the required amount from the actual amount which gives you the excess or abundance, its relative because you compare it to the required amount.
The percent abundance is the relative abundance as a percentage of the required amount.
Therefore % abundance= (abundance/required amount) X 100

The key difference is that percentages are standardised as a number out of 100 which allows you to compare them with other percentages without any calculations.

Hope that helps.

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How many parts per million of lead is found in 250 ml of water if there is 1.30g of lead in the water? 1ml=1g

SSSSS [86.1K]

Answer:

5200 ppm

Explanation:

As per the definition, parts per million of a contaminant is a measure of the amount of mass of contaminant present per million amount of the solution. It is denoted by ppm.

Given in the question,

Water = 250 ml = 250 g

Lead = 1.30 g

So,

ppm of Lead = $\frac{Lead}{Water} \times 10^6$ = $\frac{1.30}{250} \times 10^6$ = 5200 ppm

So, as calculated above, there is 5200 ppm of lead present in 250 ml of water.

6 0

3 years ago

In the lab, it is relatively easy to measure the activity of a sample and to estimate the mass of carbon in the sample. from the

miss Akunina [59]

It is not possible to find the age of a sample when just knowing activity of the sample and mass of the sample.

3 0

3 years ago

(Numerical problems) A car is running with the velocity of 72km/h. What will be it's velocity after 5s if it's acceleration is -

kodGreya [7K]

The car's velocity after 5s : 10 m/s

<h3>Further explanation</h3>

Given

velocity=v=72 km/h=20 m/s

time=t = 5 s

acceleration=a = -2 m/s²

Required

velocity after 5s

Solution

Straight motion changes with constant acceleration

$\tt v_f=v_i+at$

vf=final velocity

vi = initial velocity

Input the value :

$\tt v_f=20+(-2).5\\\\v_f=20-10\\\\v_f=10~m/s$

The car is decelerating (acceleration is negative) so that its speed decreases

4 0

3 years ago

Explain by means of why is reddish orange is observed when you add sodium chloride

Lemur [1.5K]

Answer:

because the orange is unripe

6 0

3 years ago

How many moles of solute particles are present in 1 ml of aqueous 0.020 m (nh4)2co3?

Dima020 [189]

Vs = 1.0 mL = 0.001 L
c((NH4)2CO3) = <span>0.02 M
n(</span>(NH4)2CO3) = ?

For the purpose, here we will use the next equation:

c=n/V ⇒ n=cxV

n((NH4)2CO3) = 0.02M x 0.001L

n((NH4)2CO3) = 2x10⁻⁵ mole of (NH4)2CO3 is presented in the solution

6 0

3 years ago