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Dafna1 [17]
3 years ago
5

Find the area of a regular hexagon with a 48-inch perimeter.

Mathematics
2 answers:
kiruha [24]3 years ago
7 0
A= \cfrac{3 \sqrt{3} }{2}*a^2 \ \ \ \ [a=sidelength]  \\   \\ a=48/6=8 \ in \\ \\ \\ A= \cfrac{3 \sqrt{3} }{2}*(8)^2=A= \cfrac{3 \sqrt{3} }{2}*64=3 \sqrt{3}*32= 96 \sqrt{3} \ \ in^2
Oduvanchick [21]3 years ago
7 0

The answer is: 96√3 in2

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4 0
3 years ago
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3 years ago
Name the binomial you can multiply by (x + 9) to get the product x^2 + 5x- 36
SpyIntel [72]
If you would like to solve (x^2 + 5x - 36) / (x + 9), you can do this using the following steps:

a = ?
(x + 9) * (x + a) = <span>(x^2 + 5x - 36)
x^2 + ax + 9x + 9a = x^2 + 5x - 36
ax + 9x = 5x
a + 9 = 5
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The correct result would be x - 4.
</span>
5 0
3 years ago
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