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3 years ago

-|5a+b| + |3y+2z|

Mathematics

1 answer:

mel-nik [20]3 years ago

5 0

Answer:

- 12.4

Step-by-step explanation:

Substitute the given values into the expression

- | 5(- 2) + (- 3) | + | 3(3) + 2(- 4.2) |

= - | - 10 - 3 | + | 9 - 8.4 |

= - | - 13 | + | 0.6 |

= - | 13 | + | 0.6 |

= - 13 + 0.6

= - 12.4

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Apply the distributive property to produce an equivalent expression to 10(9+8t

Ket [755]

10(9+8t)
10x9+10x8t
90+8t
hope that helps

5 0

3 years ago

A drawer contains 6 black neckties, 2 white neckties,4 red neckties,2 maroon neckties and 2 blue neckties. One necktie is picked

kogti [31]

A) The probability of picking a white tie 300 times = $(\frac{1}{8}) ^{300}$

B) The probability of picking a blue tie 300 times = $(\frac{1}{8}) ^{300}$

C) The probability of picking a red tie 300 times = $(\frac{1}{4}) ^{300}$

D) the probability of picking a black tie 300 times = $(\frac{3}{8}) ^{300}$

E ) the probability of picking a maroon tie 300 times = $(\frac{1}{8}) ^{300}$

F) the probability of NOT picking a white tie 300 times = $(\frac{7}{8}) ^{300}$

Step-by-step explanation:

Here, the total number of black neckties = 6

The total number of white neckties = 2

The total number of red neckties = 4

The total number of maroon neckties = 2

The total number of blue neckties = 2

The number of times the experiment is repeated = 300

A ) P(Picking a white tie) = $\frac{\textrm{Total number of white ties}}{\textrm{Total Bow ties}}$

= $\frac{2}{16} = \frac{1}{8}$

So, the probability of picking a white ONCE is 1/8.

Now, as the experiment is REPEATED 300 times with replacement.

So, the probability of picking a white tie 300 times = $(\frac{1}{8}) ^{300}$

B) P(Picking a BLUE tie) = $\frac{\textrm{Total number of blue ties}}{\textrm{Total Bow ties}} = \frac{2}{16} = \frac{1}{8}$

So, the probability of picking a blue ONCE is 1/8.

Hence, the probability of picking a blue tie 300 times = $(\frac{1}{8}) ^{300}$

C) P(Picking a Red tie) = $\frac{\textrm{Total number of Red ties}}{\textrm{Total Bow ties}} = \frac{4}{16} = \frac{1}{4}$

So, the probability of picking a red ONCE is 1/4.

Hence, the probability of picking a red tie 300 times = $(\frac{1}{4}) ^{300}$

D) P(Picking a Black tie) = $\frac{\textrm{Total number of black ties}}{\textrm{Total Bow ties}} = \frac{6}{16} = \frac{3}{8}$

So, the probability of picking a red ONCE is 3/8.

Hence, the probability of picking a black tie 300 times = $(\frac{3}{8}) ^{300}$

E) P(Picking a maroon tie) = $\frac{\textrm{Total number of maroon ties}}{\textrm{Total Bow ties}} = \frac{2}{16} = \frac{1}{8}$

So, the probability of picking a maroon ONCE is 1/8.

Hence, the probability of picking a maroon tie 300 times = $(\frac{1}{8}) ^{300}$

F) P(Picking a NOT whiten tie) = 1 - P( picking a white tie)

$= 1-(\frac{1}{8} ) = \frac{8-1}{8} = (\frac{7}{8} )$

So, the probability of NOT picking a white ONCE is 7/8.

Hence, the probability of NOT picking a white tie 300 times = $(\frac{7}{8}) ^{300}$

4 0

3 years ago

I am once again asking for your mathematical support

zvonat [6]

Step-by-step explanation:

$\frac{30}{200} \times 100 \\ \\ = \frac{30}{2} \\ \\ = 15 \% \\$

3 0

3 years ago

Solve for Y. 1/8 > y > 18%

Advocard [28]

Answer:

The solution is (-∞, 0.125) ∪ (0.18,∞)

Step-by-step explanation:

we have

$\frac{1}{8} > y > 18\%$

This is a compound inequality

$y > 18\%$ or $y < \frac{1}{8}$

Remember that

$18\%=18/100=0.18$

$\frac{1}{8}=0.125$

$y > 0.18$ -----> the solution is the interval (0.18,∞)

$y < 0.125$ ----> the solution is the interval (-∞, 0.125)

The solution of the compound inequality is

(-∞, 0.125) ∪ (0.18,∞)

3 0

4 years ago

Please help! Suppose f(x) = x - 4. Find the graph of

Molodets [167]

Answer:

Graph 1 because if you just do the Y coordinate its much easier.

3 0

3 years ago

Read 2 more answers