A student performs an exothermic reaction in a beaker and measures the temperature. If the thermometer initially reads 35 degree
1 answer:
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Answer:
See explanation below
Explanation:
You are not providing the starting material, however, I manage to find a similar question to this, so I'm gonna use it as a basis to help you answer yours.
Now let's analyze what is happening in the reaction so we can predict the final product.
We have a ketone here, reacting at first with LDA. This is a very strong base that is commonly used in reactions with ketones and aldehydes to promove a condensation. To do this, as LDA is a strong base it will occur firts an acid base reaction, substracting the most acidic hydrogen in the molecule (Which in this case, is the Beta hydrogen of the carbonile). This will cause an enolate formation.
Then, this enolate will react with the CH3I and form a new product. The final result would be a ketone with a methyl group now attached. In the picture 2, you have the mechanism and final product.
Hope this helps
Explanation:
The given data is as follows.
= 0.483,
= 0.173 M,
= 0.433 M,
= 0.306 M,
= 9.0 atm
According to the ideal gas equation, PV = nRT
or, P =
Also, we know that
Density =
So, P = MRT
and, M =
=
=
= 0.368 mol/L
Now, we will calculate the cell potential as follows.
E =
=
=
=
= 0.483 - 0.0185
= 0.4645 V
Thus, we can conclude that the cell potential of given cell at is 0.4645 V.