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3 years ago

Suppose you needed to cool off 19.8 grams of water at 33.3 °C to 28 °C. Calculate the energy released in this process.

Chemistry

1 answer:

crimeas [40]3 years ago

4 0

<h2>Answer: 439.07 J</h2>

Explanation:

The energy released can be calculated using the formula Q = mcΔT; here Q is the heat energy transferred (in joules), m is the mass of the liquid being cooled (in grams), c is the specific heat capacity of the liquid (joule per gram degrees Celsius), and ΔT is the change in temperature.

since m = 19.8 g

c = 4.184 J/g ·°C

ΔT = 33.3 °C - 28 °C = 5.3 °C

⇒ Q = (19.8 g) (4.184 J/g ·°C)(5.3 °C)

Q = 439.07 J

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Sauron [17]

The question is missing parts. The complete question is as follows.

Consider the two gaseous equilibria involving SO2 and the corresponding equilibrium constants at 298K:

$SO_{2}_{(g)} + \frac{1}{2}O_{2}$ ⇔ $SO_{3}_{(g)}$ ; $K_{1}$

$2SO_{3}_{(g)}$ ⇔ $2SO_{2}_{(g)}+O_{2}_{(g)}; K_{2}$

The values of the equilibrium constants are related by:

a) $K_{1}$ = $K_{2}$

b) $K_{2} = K_{1}^{2}$

c) $K_{2} = \frac{1}{K_{1}^{2}}$

d) $K_{2}=\frac{1}{K_{1}}$

Answer: c) $K_{2} = \frac{1}{K_{1}^{2}}$

Explanation: <u>Equilibrium</u> <u>constant</u> is a value in which the rate of the reaction going towards the right is the same rate as the reaction going towards the left. It is represented by letter K and is calculated as:

$K=\frac{[products]^{n}}{[reagents]^{m}}$

The concentration of each product divided by the concentration of each reagent. The indices, m and n, represent the coefficient of each product and each reagent.

The equilibrium constants of each reaction are:

$SO_{2}_{(g)} + \frac{1}{2}O_{2}$ ⇔ $SO_{3}_{(g)}$

$K_{1}=\frac{[SO_{3}]}{[SO_{2}][O_{2}]^{1/2}}$

$2SO_{3}_{(g)}$ ⇔ $2SO_{2}_{(g)}+O_{2}_{(g)}$

$K_{2}=\frac{[SO_{2}]^{2}[O_{2}]}{[SO_{3}]^{2}}$

Now, analysing each constant, it is easy to see that $K_{1}$ is the inverse of $K_{2}$ .

If you doubled the first reaction, it will have the same coefficients of the second reaction. Since coefficients are "transformed" in power for the constant, the relationship is:

$K_{2}=\frac{1}{K_{1}^{2}}$

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olga2289 [7]

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ANEK [815]

Answer:

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Explanation:

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3 years ago

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jeyben [28]

non-Metals:

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Oxygen.

Helium.

Sulfur.

Chlorine.

Explanation/Answer:

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Nikitich [7]

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