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3 years ago

Hi! help me please. CALCULATE THE NUMBER OF MOLECULES FOUND IN 8 MOL OF WATER?

Chemistry

1 answer:

kvasek [131]3 years ago

4 0

Answer:

so the number of molecules in 8 moles of water is 4.8176×10^24

Explanation:

number of moles=8moles

avogadro's number=6.022×10²³

number of molecules=?

as we know that

$number of moles=\frac{number of molecules}{avogadro's number}$

substituting the equation

number of moles × avogdro's number=number of molecules

number of molecules=8moles×6.022×10²³

number of molecules=4.8176×10^24

i hope this will help you :)

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How many atoms are in 0.625 moles of ge (atomic mass = 72.59 amu)?

lord [1]

0.625 moles of ge X 6.02x10^23 atoms/ 1 mol of ge equal to 3.76x10^23 atoms of ge, just times with Avogadro.

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3 years ago

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At a temperature of 280 K, the gas in a cylinder has a volume of 20.0 liters. If the volume of the gas is decreased to 10.0 lite

seraphim [82]

To solve this we assume that the gas inside is an ideal gas. Then, we can use the ideal gas equation which is expressed as PV = nRT. At a constant pressure and number of moles of the gas the ratio T/V is equal to some constant. At another set of condition of temperature, the constant is still the same. Calculations are as follows:

T1 / V1 = T2 / V2

T2 = T1 x V2 / V1

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3 years ago

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A chemical engineer must calculate the maximum safe operating temperature of a high-pressure gas reaction vessel. The vessel is

Airida [17]

Answer:

the maximum safe operating temperature the engineer should recommend for this reaction is 616 °C

Explanation:

Given the data in the question;

First we calculate the Volume of the steel cylinder;

V = πr²h

radius r = Diameter / 2 = 27 cm / 2 = 13.5 cm

height h = 32.4 cm

so we substitute

V = π × ( 13.5 cm )² × 32.4 cm

V = π × 182.25 cm × 32.4 cm

V = 18550.79 cm³

V = 18.551 L

given that; maximum safe pressure P = 3.10 MPa = 30.5946 atm

vessel contains 0.218kg or 218 gram of carbon monoxide gas

molar mass of carbon monoxide gas is 28.010 g/mol

moles of carbon monoxide gas n = 218 gram / 28.010 g/mol = 7.7829 mol

we know that;

PV = nRT

solve for T

T = PV / nR

we know that gas constant R = 0.0820574 L•atm•mol⁻¹ K⁻¹

so we substitute

T = ( 30.5946 × 18.551 ) / ( 7.7829 × 0.082 )

T = 567.5604 / 0.6381978

T = 889.317387 K

T = ( 889.317387 - 273.15 ) °C

T = 616.167 ≈ 616 °C { 3 significant digits }

Therefore, the maximum safe operating temperature the engineer should recommend for this reaction is 616 °C

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3 years ago

What mass in grams of SO2 is needed to react with 37.50 mol of Oz?

-BARSIC- [3]

Answer:

4804.5 g of SO₂ are needed to the reaction

Explanation:

The reaction to produce sulfuric acid is:

2SO₂ + O₂ + 2H₂O → 2H₂SO₄

Ratio is 1:2. 1 mol of oxygen needs 2 moles of sulfur dioxide in order to react. We can propose this rule of three.

If 1 mol of O₂ react to 2 moles of SO₂

Then, 37.50 moles of O₂ will react with (37.5 . 2) /1 = 75 moles of SO₂

We convert the moles to mass, to know the answer:

75 mol . 64.06 g / 1 mol = 4804.5 g of SO₂

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3 years ago

A chemist needs 0.550 mol selenium for a reaction. What mass of selenium should a chemist use?

-BARSIC- [3]

Answer:

The chemist would require to use 43.43 grams.

Explanation:

In order to solve this problem we need to know how much do 0.550 moles of selenium weigh. To do that we use selenium's molar mass and multiply it by the given number of moles:

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The chemist would require to use 43.43 grams.

4 0

3 years ago