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Sever21 [200]
2 years ago
13

1.Give an example of a compound machine (1pt). Explain how at least two simple machines are part of this compound machine (2pts)

.
Chemistry
1 answer:
Law Incorporation [45]2 years ago
4 0
1) An example of a compound machine could be a pair of Scissors. Their are two different simple machines in the Scissors which make up the compound machine. Both of them being a Lever, and a Fulcrum.

Hope this helps!
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Why will paper stick to a ballon that you have rubbed on your hair?
Usimov [2.4K]
Depending on the balloon, the surface will cause friction between the two and oxygen molecules will fuse together to create a sticky sensation
7 0
3 years ago
A solution of hydrocloric acid has a molarity of 2.25 M HCl. If a reaction requires 5.80 g of HCI, what
Natali [406]

Answer:

0.071L

Explanation:

From the question given, we obtained the following data:

Molarity of HCl = 2.25 M

Mass of HCl = 5.80g

Molar Mass of HCl = 36.45g/mol

Number of mole of HCl =?

Number of mole = Mass /Molar Mass

Number of mole of HCl = 5.8/36.45 = 0.159mole

Now, we can obtain the volume required as follows:

Molarity = mole /Volume

Volume = mole /Molarity

Volume = 0.159mole/ 2.25

Volume = 0.071L

4 0
3 years ago
C) Mercury is solid at room temperature....True Or False<br>​
Zielflug [23.3K]

Answer:

true

Explanation:

Because Mercury can be solidified when its temparature us brought to its freezing point. However, when returned to room temparature conditions, mercury does not exist in solid state for long, and returns back to its more common liquid form.

7 0
3 years ago
Now let us refine our model by noting that there is a second source of Na+ ions in the cell: NaI. Suppose the outside of the cel
MArishka [77]

Answer:

E=55mV

Explanation:

Hello,

Considering the given information, the new concentration of Na+inside will be (13.6 + 4) mM = 17.6 mM, and outside will be (150 + 0.04) mM = 150.04 mM due to the previous specified conditions.

Now, the recalculation of the Nerst potential at the supposed temperature of 25 °C (which is modifiable) is done via:

E=\frac{RT}{zF} ln(\frac{C_{Na^+,outside}}{C_{Na^+,outside}} )\\\\E=\frac{8.314\frac{J}{mol*K}*298K}{1*9.65x10^4\frac{C}{mol} } *ln(\frac{150.04}{17.6} )=0.055V*\frac{1x10^3mV}{1V} \\E=55mV

Best regards.

8 0
2 years ago
Volcanoes emit much hydrogen sulfide gas, h2s, which reacts with the oxygen in the air to form water and sulfur dioxide, so2. ev
liq [111]

Answer: There will be 131.3 tons of SO_{2} that will be generated.


Explanation : We have the data as 72 tons of H_{2}S, O_{2} is 101 tons and H_{2}O as 38 tons.


Conversion of 1 ton to kg will be approximately 907.2 Kg


We have to convert the given data of tons into kg for all;


So, moles of H_{2}S = (72 tons X 907.2 Kg/ton X 1000 g/Kg) / (34.082 g/ mol) = 1.916 X 10^{6} moles

Now, moles of O_{2} = (101 tons X 907.2 Kg/ton X 1000 g/Kg) / (32 g/mol) = 2.80 X10^{6} moles

And, H_{2}O = (38 tons X 907.2 Kg/ton X 1000 g/Kg) / (18.016 g/mol)

= 1.03 X 10^{6} moles


Now, we have to calculate the moles of H_{2}S

so, 1.916 X 10^{6} moles / 2 moles of H_{2}S = 958 X 10^{3}


Now, for O_{2} ;

So, 2.80 X10^{6} moles / 3 moles of O_{2} = 933.3 X 10^{3} moles


Here, we can see that O_{2} is acting as a limiting reactant.


Now, moles of SO_{2} = 2.80 X10^{6} X (2 moles of SO_{2} / 3 moles of O_{2}) = 1.86 X 10^{6}


Now converting this into mass,


Mass = Moles X Molar Mass

Mass = 1.86 X 10^{6} X (64.066 g/mol X 10^{-3} kg/g) X (1 ton / 907.2 Kg)

= 131.3 tons of SO_{2}

7 0
3 years ago
Read 2 more answers
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