<h2> The correct option is (a).</h2>
Explanation:
- There is no change of state in pouring water into a vacuum insulated bottle as the vacuum created inside the bottle only reduces the time limit for the transfer of heat by conduction and convection.
- It helps the content filled in the bottle to be hot and cool for a longer time.
Hence, option (a) is correct.
Rest of the options (b), (c), (d), (e) is not correct because of the following reasons:
- In the sublimation of dry ice, the dry ice (solid-state) is changed to the vapour form.
- In the freezing of water, the liquid state is changed to solid-state.
- During the vaporization of alcohol, the liquid state is changed to the vapour form.
- During the melting of ice, the solid-state is changed to the liquid state.
Dividing the mass by the volume.
In such type of problems where reactant and product ratios are calculated one (Launa) should take start from balanced chemical equation. A balanced chemical equations helps in solving such problems. For this purpose chemical equation of this combustion reaction is drawn.
Equation:
C₃H₁₀ ⁺ 5 O₂ ⁻⁻⁻⁻⁻⁻⁻⁻⁻> 3 CO₂ ⁺ 4 H₂O
Now, According to this balanced equation one molecule of propane reacts with 5 molecules of oxygen to produce 3 molecules of carbon dioxide and 4 molecules of water.
As She is given with 2 molecules of propane and 10 molecules of oxygen, which means that the equation is multiplied by 2. So, the product side must also be multiplied by 2 to balance the equatio (Law of Conservation of Mass).
Result:
( C₃H₁₀ ⁺ 5 O₂ ⁻⁻⁻⁻⁻⁻⁻⁻⁻> 3 CO₂ ⁺ 4 H₂O ) ₓ 2
2 C₃H₁₀ ⁺ 10 O₂ ⁻⁻⁻⁻⁻⁻⁻⁻⁻> 6 CO₂ ⁺ 8 H₂O
So, 6 molecules of carbon dioxide and 8 molecules of water are produced.
The higher the temperature of the gas, the faster the molecules move as they approach evaporating temperature. The lower the temperature of the gas, the slower the molecules move as they approach cooling temperature. The temperature controls how fast the molecules move
