Answer:
the height is : 2365.48 m
Step-by-step explanation:
hello :
h(t) = − 4.9 t 2 + 211 t + 94 .
the vertex of this parabola is : (-b/2a , h(-b/2a) when : a= -4.9 and b=211
-b/2a = -(211)/2(-4.9) = 21.53
h(21.53) = -4.9(21.53)²+211(21.53)+94 = 2365.48 m
1.6 % of 43.75 is 70
Because 70/43.75 is 1.6
Answer:
Step-by-step explanation:
In order to find the horizontal distance the ball travels, we need to know first how long it took to hit the ground. We will find that time in the y-dimension, and then use that time in the x-dimension, which is the dimension in question when we talk about horizontal distance. Here's what we know in the y-dimension:
a = -32 ft/s/s
v₀ = 0 (since the ball is being thrown straight out the window, the angle is 0 degrees, which translates to no upwards velocity at all)
Δx = -15 feet (negative because the ball lands 15 feet below the point from which it drops)
t = ?? sec.
The equation we will use is the one for displacement:
Δx = 
and filling in:
which simplifies down to
so
so
t = .968 sec (That is not the correct number of sig fig's but if I use the correct number, the answer doesn't come out to be one of the choices given. So I deviate from the rules a bit here out of necessity.)
Now we use that time in the x-dimension. Here's what we know in that dimension specifically:
a = 0 (acceleration in this dimension is always 0)
v₀ = 80 ft/sec
t = .968 sec
Δx = ?? feet
We use the equation for displacement again, and filling in what we know in this dimension:
Δx = 
and of course the portion of that after the plus sign goes to 0, leaving us with simply:
Δx = (80)(.968)
Δx = 77.46 feet
Answer:
0.347
Step-by-step explanation:
n = 3
p = 1/6
r = 1
Use binomial probability:
P = nCr pʳ qⁿ⁻ʳ
P = ₃C₁ (1/6)¹ (5/6)³⁻¹
P = 0.347
Or, using a calculator:
P = binompdf(n, p, r)
P = binompdf(3, 1/6, 1)
P = 0.347
The correct answer is: [D]: " <span>x-int : 1 , y-int: 0.5 " .
_____________________________________________________
Note:
_____________________________________________________
The "x-intercept" refers to the point(s) at which the the graph of a function (which is a "line", in this case) cross(es) the "y-axis".
In other words, what is (are) the point(s) of the graph at which "x = 0<span>" ?
</span>
By examining the graph, we see that when " x = 0" ; y is equal to: "1<span>" .
</span>
So; the "x-intercept" is at point: "(0, 1)" ; or, we can simply say that the
"x-intercept" is: "1" .
_________________________________________________________</span> Note:
_____________________________________________________
The "y-intercept" refers to the point(s) at which the the graph of a function (which is a line, in this case) cross(es) the "x-axis".
In other words, what is (are) the point(s) of the graph at which " y = 0 <span>" ?
</span>
By examining the graph, we see that when " y = 0 " ; x is equal to: "0.5<span>" .
</span>
So; the "x-intercept" is at point: "(0.5, 0)" ; or, we can simply say that the
"y-intercept" is: "0.5 " .<span>
______</span>_________________________________________________
This would correspond to:<span>
_______________________________________________________
Answer choice: [D]: </span>" x-int: 1 , y-int: 0.5 " .
_______________________________________________________
{that is; The "x-intercept" is: "0" ; and the "y-intercept" is: "0.5 ".} .
_______________________________________________________
