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umka2103 [35]
3 years ago
11

In every balanced chemical equation each side of the equation has the same number of

Chemistry
1 answer:
nekit [7.7K]3 years ago
3 0
In a balanced chemical equation each side has the same number of ATOMS of the reactants.

For example(This is random)

2C + 2O = 2C2O

I still have 2 Carbon and 2 Oxygen atoms after the reaction.
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A 475 ml sample of a gas was collected at room temperature of 23.5 °C and a pressure of
Molodets [167]

Answer:

The volume when the conditions were altered is 0.5109 L or 510.9 mL

Explanation:

Using the general gas equation,

P1 V1 / T1 = P2 V2 / T2

where;

P1 = 756 mmHg

V1 = 475 ml = 0.475 L

T1 = 23.5°C = 23.5 + 273K = 275.5 K

P2 = 722 mm Hg

T2 = 10°C = 10 + 273 K = 283 K

V2 = ?

Rearranging to make V2 the subject of the formula, we obtain:

V2 = P1 V1 T2 / P2 T1

V2 = 756 * 0.475 * 283 / 722 * 275.5

V2 = 101, 625.3 / 198911

V2 = 0.5109 L or  510.9 mL

3 0
4 years ago
An atom becomes negatively charged by
Pavlova-9 [17]
If it gains a electron
4 0
3 years ago
Read 2 more answers
What new scientific evidence led to changes in Dalton's atomic theory?
Masja [62]

Drawbacks of Dalton's Atomic Theory. The indivisibility of an atom was proved wrong: an atom can be further subdivided into protons, neutrons and electrons. However an atom is the smallest particle that takes part in chemical reactions. According to Dalton, the atoms of same element are similar in all respects.

6 0
3 years ago
How did Wilma contribute to change in America
Natasha_Volkova [10]

Answer:

She overcame her disabilities to compete in the 1956 Summer Olympic Games, and in 1960, she became the first American woman to win three gold medals in track and field at a single Olympics. Later in life, she formed the Wilma Rudolph Foundation to promote amateur athletics.

Explanation:

3 0
3 years ago
A 1.50 g sample of solid NH₄NO₃ was added to 35.0 mL of water in a styrofoam cup (insulated from the environment) and stirred un
GaryK [48]

Answer : The heat of the reaction is, 1.27 kJ/mole

Explanation :

First we have to calculate the heat released.

Formula used :

Q=m\times c\times \Delta T

or,

Q=m\times c\times (T_2-T_1)

where,

Q = heat = ?

m = mass of sample = 1.50 g

c = specific heat of water = 4.81J/g^oC

T_1 = initial temperature  = 22.7^oC

T_2 = final temperature  = 19.4^oC

Now put all the given value in the above formula, we get:

Q=1.50g\times 4.81J/g^oC\times (19.4-22.7)^oC

Q=-23.8095J=-0.0238kJ

Now we have to calculate the heat of the reaction in kJ/mol.

\Delta H=\frac{Q}{n}

where,

\Delta H = enthalpy change = ?

Q = heat released = 0.0238 kJ

n = number of moles NH₄NO₃ = \frac{\text{Mass of }NH_4NO_3}{\text{Molar mass of }NH_4NO_3}=\frac{1.50g}{80g/mol}=0.01875mole

\Delta H=\frac{0.0238kJ}{0.01875mole}=1.27kJ/mole

Therefore, the heat of the reaction is, 1.27 kJ/mole

8 0
3 years ago
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