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trasher [3.6K]
3 years ago
10

How do you write 8.08 × 104 in standard form?

Mathematics
1 answer:
Goryan [66]3 years ago
8 0

Answer:

840.32

Step-by-step explanation:

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A veterinarian estimated the weight of a puppy to be 7 kg. The actual weight of the puppy was 6.6 kg.
KIM [24]

9514 1404 393

Answer:

  • absolute error: 0.4 kg
  • relative error: 6.1%

Step-by-step explanation:

The absolute error is the difference between the estimate and the actual weight:

  7.0 kg -6.6 kg = 0.4 kg . . . . absolute error

__

The relative error is the ratio of the absolute error to the actual weight:

  (0.4 kg)/(6.6 kg) × 100% = 6.060606...% ≈ 6.1% . . . . relative error

6 0
3 years ago
Find the Area of the figure below,
murzikaleks [220]

Answer:

169.1 unit^2 to the nearest tenth.

Step-by-step explanation:

Area of the parallelogram = base * height

= 24 * 6 unit^2.

Area of the semicircle = 1/2 pi r^2.

Here r = 1/2 * 8 = 4.

So the area is 1/2 * pi * 4^2

= 8pi unit^2.

The area of the whole figure = 24*6 + 8pi

= 169.13 unit^2.

3 0
3 years ago
According to data from a medical​ association, the rate of change in the number of hospital outpatient​ visits, in​ millions, in
GaryK [48]

Answer:

a) f(t)=0.001155[\frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}]+264,034,000

b) f(t=2015) = 264,034,317.7

Step-by-step explanation:

The rate of change in the number of hospital outpatient​ visits, in​ millions, is given by:

f'(t)=0.001155t(t-1980)^{0.5}

a) To find the function f(t) you integrate f(t):

\int \frac{df(t)}{dt}dt=f(t)=\int [0.001155t(t-1980)^{0.5}]dt

To solve the integral you use:

\int udv=uv-\int vdu\\\\u=t\\\\du=dt\\\\dv=(t-1980)^{1/2}dt\\\\v=\frac{2}{3}(t-1980)^{3/2}

Next, you replace in the integral:

\int t(t-1980)^{1/2}=t(\frac{2}{3}(t-1980)^{3/2})- \frac{2}{3}\int(t-1980)^{3/2}dt\\\\= \frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}+C

Then, the function f(t) is:

f(t)=0.001155[\frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}]+C'

The value of C' is deduced by the information of the exercise. For t=0 there were 264,034,000 outpatient​ visits.

Hence C' = 264,034,000

The function is:

f(t)=0.001155[\frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}]+264,034,000

b) For t = 2015 you have:

f(t=2015)=0.001155[\frac{2}{3}(2015)(2015-1980)^{1/2}-\frac{4}{15}(2015-1980)^{5/2}]+264,034,000\\\\f(t=2015)=264,034,317.7

3 0
3 years ago
56 ×54 (5×6)÷ equals​
Maurinko [17]

Answer: 90,720

Step-by-step explanation: 56*54=3,024

5*6= 30

3,024*30=90,720

4 0
3 years ago
15 POINTS!!!! <br> 7 ÷ 0.1 = 7 ÷ 1/10<br><br> 7 is 1/10 of____.<br><br> Help Please
lara [203]
7 is 70 out of 1/10.

please give thanks if i am correct, i think this is the question you're asking.
7 0
3 years ago
Read 2 more answers
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