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Aleksandr-060686 [28]
2 years ago
13

9. If it takes Joel 30 seconds to install each

Mathematics
1 answer:
DaniilM [7]2 years ago
3 0

Answer:

20

Step-by-step explanation:

Since we have given that

Dimensions of a triangle he has to use for fencing are

15 feet, 8 feet, and 20 feet.

1) For making it a right triangle it must satisfy the "Pythagoras theorem" which states that

H^{2} = B^{2} + P^{2}

20^{2} = 15 + 8^{2}

400 \neq  225 + 64

400 \neq 289

No, it will not be able to make a right triangle.

2) Joel cut the longest piece of wood in order to make a right triangle.

So, from above we get that

\sqrt{} 289 = 17 feet

So, the longest side must be 17 feet.

It takes him 30 seconds to install each foot of fencing,

The total perimeter of fencing will be

17 + 15 + 8 = 40 feet

So, for 1 foot he needs = 30 seconds

For 40 feet, he will need

40 × 30 = 1,200 seconds

1200/600 = 20 minutes

Hence, he needs 20 minutes to install all of the fences.

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Given functions:

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Domain: input values (x-values)

For (f\:o\:g)(x) to be defined:

x+5\geq 0 \implies x\geq -5

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x - 1 = 0 or 2 x + 3 = 0

Add 1 to both sides:

x = 1 or 2 x + 3 = 0

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Divide both sides by 2:

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\sqrt{( x_{2} - x_{1} )^2 + (y_{2} - y_{1})^2}

 
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\sqrt{(3)^2 + (2)^2}

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\sqrt{13}

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Points S and T
\sqrt{(3 - 0)^2 + (-2 - 0)^2}

\sqrt{(3)^2 + (-2)^2}

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\sqrt{13}

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Points T and U
\sqrt{(3 - 2)^2 + (-2 + 5)^2}

\sqrt{(1)^2 + (3)^2}

\sqrt{1+9}

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Points U and V
\sqrt{(2+2)^2 + (-5 + 5)^2}

\sqrt{(4)^2 + (0)^2}

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Points V and W
\sqrt{(-2+3)^2 + (-5 + 2)^2}

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