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3 years ago

what is the slope of a line that is parallel to the line that passes through the points (2,-2) and (5,-1)

Mathematics

1 answer:

Phoenix [80]3 years ago

4 0

Answer:1/3

Step-by-step explanation:

The formula for finding slope is (y2-y1)/(x2-x1)

(-1--2)/(5-2)

1/3

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A. Equilateral B. Right C. Obtuse D. Acute E. Scalene

faltersainse [42]

Answer:

A) Scalene E) Obtuse

Detailed Explanation:

A) Scalene

This triangle would be classified as scalene because none of the angles are equal.

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E) Obtuse

This triangle would be classified as an scalene triangle because one of the angles is larger than 90 degrees.

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3 years ago

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Simplify the radical expression. √10b^4c^4 X 3√33b^3.

ICE Princess25 [194]

Answer:

4.40211148 × 1035 m4 bytes7 / s4 is might be the correct answer I did the math and this is not from the internet

Step-by-step explanation:

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2 years ago

Factor this expression. You will need to show your work for full credit. b^2-6b+8

Ostrovityanka [42]

B^2-6b+8 turns into b^2-2b-4b+8 due to the sum product pattern. which then turns into b(b-2) - 4(b-2) and then its (b-4)(b-2)

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2 years ago

A line passes through point A (14,21). A second point on the line has an x-value that is 125% of the x-value of point A and a y-

seropon [69]

Answer:

The equation of the line in point-slope form is $y-21 = - \frac{3}{2}\cdot (x-14)$ .

Step-by-step explanation:

According to the statement, let $A(x,y) = (14,21)$ and $B(x,y) = (1.25\cdot x_{A},0.75\cdot y_{A})$ . The equation of the line in point-slope form is defined by the following formula:

$y-y_{A} = m\cdot (x-x_{A})$ (1)

Where:

$x_{A}$ , $y_{A}$ - Coordinates of the point A, dimensionless.

$m$ - Slope, dimensionless.

$x$ - Independent variable, dimensionless.

$y$ - Dependent variable, dimensionless.

In addition, the slope of the line is defined by:

$m = \frac{y_{B}-y_{A}}{x_{B}-x_{A}}$ (2)

If we know that $x_{A} = 14$ and $y_{A} = 21$ , then the equation of the line in point-slope form is:

$x_{B} = 1.25\cdot (14)$

$x_{B} = 17.5$

$y_{B} = 0.75\cdot (21)$

$y_{B} = 15.75$

From (2):

$m = \frac{15.75-21}{17.5-14}$

$m = -\frac{3}{2}$

By (1):

$y-21 = - \frac{3}{2}\cdot (x-14)$

The equation of the line in point-slope form is $y-21 = - \frac{3}{2}\cdot (x-14)$ .

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3 years ago

1. (06.01 LC) 3^4 + 2 ⋅ 5 = . (Input whole numbers only.)

Serhud [2]

Answer:

Step-by-step explanation:

Because the equation is equal to 91

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3 years ago

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