The mass of magnesium chloride produced is calculated as follows
write the equation for reaction
Mg +2HCl=MgCl +H2
find the moles of each reactant
moles = mass/molar mass
moles for mass = 32.5 g/24.3 g/mol= 1.34 moles
moles for HCl = 32.5g / 95.3 g/mol=0.89 moles
HCl is the limiting reagent hence by use of mole ratio between HCl to MgCl2 which is 2:1 the moles of MgCl2 is therefore = 0.89/2 =0.445 moles
mass of MgCl2 is therefore= moles/molar mass
=0.445moles x 95.3 g/mol= 42.4 grams of MgCl2
Answer:
They might explode. I am serious.
Answer:
C: francium-221
Explanation:
First of all to get a broader perspective, every isotope of francium usually undergoes decay to form astatine, radium, or radon.
Now, Francium-223 and francium-221 are it's only isotopes that occur in nature.
However, francium-221 is the one that undergoes alpha decay to produce astatine-217.
When ethanoic acid react with methanol in the presence of H⁺ or heat it gives methyl ethanoate and water.
<h3>What is Balanced Chemical Equation ?</h3>
The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.
Now write the chemical equation
CH₃COOH + CH₃OH ⇄ CH₃COOCH₃ + H₂O
Here
CH₃COOH is Ethanoic acid (Acetic acid)
CH₃OH is Methanol (Methyl Alcohol)
CH₃COOCH₃ is Methyl ethanoate (Methyl Acetate)
H₂O is water
Thus from the above conclusion we can say that When ethanoic acid react with methanol in the presence of H⁺ or heat it gives methyl ethanoate and water.
Learn more about the Balanced Chemical Equation here: brainly.com/question/26694427
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Answer:
<em><u>A. any absorbance of light by the solvent AND the cuvette needs to be accounted for</u></em>
Explanation:
Blank calibrations are usually carried out on the spectrometer to eliminate and account for any readings that would come from absorptions of the curvette, solvents/reagents or anything that is not the main analyte we are testing for.
Hence the blank solution does not contain the analyte itself. Fingerprints should be removed from the curvette as practice. Hence the most suitable answer amongst the options is A.
I hope this was clear ad most of all, helpful.