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DedPeter [7]
2 years ago
8

How did dmitri mendeleev arrange the periodic table.

Chemistry
1 answer:
worty [1.4K]2 years ago
3 0

Answer:

order of increasing relative atomic mass

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A volume of 90.0 mL of aqueous potassium hydroxide (KOH) was titrated against a standard solution of sulfuric acid (H2SO4). What
Gemiola [76]

Answer:

The answer to your question:  0.7 M

Explanation:

Data

V of KOH = 90 ml

[KOH] = ?

V H2SO4 = 21.2 ml

[H2SO4] = 1.5 M

                       2KOH(aq)  +  H₂SO₄(aq)   →   K₂SO₄(aq)  +  2H₂O(l)

Molarity = moles / volume

moles of H₂SO₄ = (1.5) (21.2)

                           = 31.8

                    2 moles of KOH --------------  1 mol of H₂SO₄

                   x                           --------------  31.8 mol of H₂SO₄

                    x = (31.8)(2) / 1

                    x = 63.8 moles of KOH

Molarity = 63.8 / 90

             = 0.7 M

7 0
2 years ago
Hello<br>Thank you for not answering my question
julsineya [31]
**Visible confusion** no problem
4 0
3 years ago
A sealed reaction vessel initially contains 1.113×10-2 moles of water vapor and 1.490×10-2 moles of CO(g).
Molodets [167]

Answer:

Kc =\frac{[8.326x10-3]^{1} }{[1.113x10-2]^{1}[1.490x10-2]^{1}  }

Kc = 50.2059

Explanation:

1. Balance the equation

2. Use the Kc formula

Remember that pure substances, like H2 are not included on the Kc formula

4 0
3 years ago
In a motion diagram the size of the object must be less than the distance moved t or f
KATRIN_1 [288]
The awnser is false.
6 0
2 years ago
Read 2 more answers
A gas occupies 2.0 m3 at 100.0k and exerts a pressure of 100.0kPa. What volume will the gas occupy if the temperature is increas
Svetradugi [14.3K]
According to ideal gas equation, we know for 1 mole of gas: PV=RT
where P = pressure,  T = temperature, R = gas constant, V= volume
If '1' and '2' indicates initial and final experimental conditions, we have
\frac{P1V1}{P2V2} =  \frac{T1}{T2}

Given that: V1 = 100.0 kPa, T1 = 100.0 K, V1 = 2.0 m3, T2 = 400 K, P2 = 200.0 kPa

∴ on rearranging above eq., we get V2 = \frac{P1V1T2}{T1} =  \frac{100 X 2 X 400}{200X100}
∴ V2 = 4 m3 
7 0
3 years ago
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