The equation is x/25=3.2
*25 *25
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x=80g
Try to understand all the rules and laws like:
Aufbau Principle
Hund's rule
Pauli exclusion principle...
Then, you should understand the way in which you can fill the electrons in the orbitals!!
a.
Ionic bond is a bond in which there is complete transfer of valence electrons between atoms.
The atom that loses the valence electron is called the electron donor while the atom that accepts the electron is called the electron acceptor.
Ionic bond usually occurs between metals and non metals.
Ionic bond is a bond in which there is complete transfer of valence electrons between atoms.
b.
The force of attraction between Na⁺ and Cl⁻ forms the ionic bond.
- In the formation of NaCl, Na has one valence electron in its outermost shell and Cl needs one electron to complete the stable octet configuration.
- Na donates its valence electron to Cl to form the ionic bond. So, the Na atom becomes positively charged with a charge of +1 while the Cl atom becomes negatively charged with a charge of -1.
Since the atoms are now charged, the force of attraction between them forms the ionic bond.
c.
The force of attraction between Mg²⁺ and O²⁻ forms the ionic bond.
- In the formation of MgO, Mg has two valence electrons in its outermost shell and O needs two electrons to complete the stable octet configuration.
- Mg donates its two valence electron to O to form the ionic bond. So, the Mg atom becomes positively charged with a charge of +2 while the O atom becomes negatively charged with a charge of -2.
Since the atoms are now charged, the force of attraction between them forms the ionic bond.
Learn more about ionic bond here:
brainly.com/question/13526463
Answer:
How many moles KCl in 1 grams? The answer is 0.013413582325
1 mole is equal to 1 moles KCl, or 74.5513 grams.
447.3078 is the answer
Explanation:
<em>~Cornasha_Weeb</em>
2Ag⁺(aq) + Mg(s)→ 2Ag(s) + Mg²⁺ (aq)
<h3>Further explanation</h3>
Given
Standard cell notation:
Mg(s) | Mg2+ (aq) || Ag+(aq)| Ag(s)
Required
a balanced redox reaction
Solution
At the cathode the reduction reaction occurs, the anode oxidation reaction occurs
In reaction:
Ag⁺ + Mg → Ag + Mg²⁺
half-reactions
- at the cathode (reduction reaction)
Ag⁺ (aq) + e⁻ ---> Ag (s) x2
2Ag⁺ (aq) + 2e⁻ ---> 2Ag (s)
- at the anode (oxidation reaction)
Mg (s) → Mg²⁺ (aq) + 2e−
a balanced cell reaction
<em>2Ag⁺(aq) + Mg(s)→ 2Ag(s) + Mg²⁺ (aq)
</em>
