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Alex
2 years ago
8

Please!!!!!!!!!!!!!!!!!!!!!!!

Chemistry
1 answer:
maria [59]2 years ago
3 0

Answer:

yesir

Explanation:

yesir yesir yesssirrrr

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I need an answer now please asap and you will me marked brainiest please it's missing I need it now.
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Where are the question's???

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What is in the solar system?
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Calculate the mass (in grams) of 8.56 moles of sulfur.
oksano4ka [1.4K]

Answer:

275g

Explanation:

Depending on the molar mass you are given, you can use that to solve this.

(I'm going based on my science class' molar mass of sulphur being 32.07g/mol)

Starting off, the formula for finding moles is

n=m/M (moles = mass / molar mass)

We can manipulate this equation to solve for mass.

m=Mn

now fill in what we now.

m = 32.07*8.56

mass = 274.5192

Now round for significant digits (if you are needed to do)

mass = 275g

5 0
3 years ago
Draw the structures of the two monomers that react together to form this polyurethane polymer
matrenka [14]

The monomers that react together to form polyurethane polymer are diisocyanate and diol.

<h3>What are polymers?</h3>
  • Polymers are a class of natural or synthetic substances
  • It is made up of small units called monomers arranged in a repeated pattern to form large molecules called macromolecules
  • Cellulose and resins are examples of natural polymers
  • Polyethylene and polychloroprene are examples of synthetic polymers.

Polyurethane polymer is made up of monomers diisocyanate and diol. It is mostly used in home furnishing in flexible form. The structures of monomers are as follows:

Learn more about polymers:

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7 0
1 year ago
Number of grams of hydrogen than can be prepared from 6.80g of aluminum​
Anastaziya [24]

Answer:

0.7561 g.

Explanation:

  • The hydrogen than can be prepared from Al according to the balanced equation:

<em>2Al + 6HCl → 2AlCl₃ + 3H₂,</em>

It is clear that 2.0 moles of Al react with 6.0 mole of HCl to produce 2.0 moles of AlCl₃ and 3.0 mole of H₂.

  • Firstly, we need to calculate the no. of moles of (6.8 g) of Al:

no. of moles of Al = mass/atomic mass = (6.8 g)/(26.98 g/mol) = 0.252 mol.

<em>Using cross multiplication:</em>

2.0 mol of Al produce → 3.0 mol of H₂, from stichiometry.

0.252 mol of Al need to react → ??? mol of H₂.

∴ the no. of moles of H₂ that can be prepared from 6.80 g of aluminum = (3.0 mol)(0.252 mol)/(2.0 mol) = 0.3781 mol.

  • Now, we can get the mass of H₂ that can be prepared from 6.80 g of aluminum:

mass of H₂ = (no. of moles)(molar mass) = (0.3781 mol)(2.0 g/mol) = 0.7561 g.

5 0
3 years ago
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