All categories

3 years ago

Judging by appearance, name an obtuse angle, an acute angle, and a right angle.

Mathematics

1 answer:

xxTIMURxx [149]3 years ago

6 0

Answer:

A.) Angle R, Angle S, Angle T

Step-by-step explanation:

It's a because it asked in order for an obtuse, an acute, and right. So in order it's R (for obtuse), S (for acute), and T (for right)

You might be interested in

Need help. Need to know how to work it out

Usimov [2.4K]

Answer:

Daniel only

Step-by-step explanation:

If you take 72 inches and convert it into yards you get 2 yards.

(divide the length value by 36. so 72 divided by 36 and you get 2 yards)

4 0

4 years ago

Read 2 more answers

Out of 90 scientists who study dinosaurs, 30 study the T-Rex, 22 study the Brontosaurs and 10 study both. How many of this group

adell [148]

Answer:

it 152 u have to add 3 time like this

90+10+30+ it gives you 152

Step-by-step explanation:

hope this works or help

4 0

2 years ago

What is the magnitude (size) of 3.7?

navik [9.2K]

The answers b. |3.7| = 3.7 so the answer will be 3.7

6 0

3 years ago

In 1998, as an advertising campaign, the Nabisco Company announced a "1000 Chips Challenge," claiming that every 18-ounce bag of

Phoenix [80]

Answer:

A 95% confidence interval for the mean number of chips in a bag of Chips Ahoy Cookies is [1187.96, 1288.44].

Step-by-step explanation:

We are given that statistics students at the Air Force Academy (no kidding) purchased some randomly selected bags of cookies and counted the chocolate chips.

Some of their data are given below; 1219, 1214, 1087, 1200, 1419, 1121, 1325, 1345, 1244, 1258, 1356, 1132, 1191, 1270, 1295, 1135.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean number of chocolate chips = $\frac{\sum X}{n}$ = 1238.2

s = sample standard deviation = $\sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }$ = 94.3

n = sample of car drivers = 16

$\mu$ = population mean number of chips in a bag

Here for constructing a 95% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation.

So, 95% confidence interval for the population mean, $\mu$ is ;

P(-2.131 < $t_1_5$ < 2.131) = 0.95 {As the critical value of t at 15 degrees of

freedom are -2.131 & 2.131 with P = 2.5%}

P(-2.131 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 2.131) = 0.95

P( $-2.131 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $2.131 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-2.131 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.131 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

95% confidence interval for $\mu$ = [ $\bar X-2.131 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+2.131 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $1238.2-2.131 \times {\frac{94.3}{\sqrt{16} } }$ , $1238.2+2.131 \times {\frac{94.3}{\sqrt{16} } }$ ]

= [1187.96, 1288.44]

Therefore, a 95% confidence interval for the mean number of chips in a bag of Chips Ahoy Cookies is [1187.96, 1288.44].

7 0

3 years ago

Eighty students try out for the school play. Of these students, 60% are given roles in the play. Males are assigned 25% of the r

klemol [59]

12 males.

60% of 80 is 48, 25% of 48 is 12

5 0

3 years ago

Read 2 more answers