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soldier1979 [14.2K]
3 years ago
5

A card is chosen at random from a standard deck of 52 playing cards.

Mathematics
1 answer:
nika2105 [10]3 years ago
4 0

Answer:

a

we dont really know so we give it a 50 50 chance

You might be interested in
The square shown has sides of length 7z^5 decimeters. Find its area
VikaD [51]

For this case we have that by definition, the area of a square is given by:

A = l ^ 2

Where:

l: It's the side of the square

We have, according to the statement data, that:

l = 7z ^ 5 \ dm

Then, the area is given by:

A = (7z ^ 5 \ dm) ^ 2

By definition of power properties we have to:

(a ^ n) ^ m = a ^ {n * m}

So:

A = (7z ^ 5 \ dm) ^ 2 = 49z^{5 * 2} \ dm ^ 2 = 49z^{10} \ dm ^ 2

Answer:

The area of the square is: 49z^{10} \ dm ^ 2

6 0
4 years ago
James and Terry open a savings account that has a 2.75% annual interest rate, compounded monthly. They deposited $500 into the a
zhuklara [117]

Answer:

$275

Step-by-step explanation:

This is what I got:

You first <u>convert</u> 2.75% into 0.0275

You then <u>multiply</u> 500 x 0.0275 = 13.75

Finally you <u>multiply</u> 13.75 x 20 = 275

so the answer should be 275

5 0
4 years ago
Divide, using the polynomial long division algorithm. Fill in your work below
dimulka [17.4K]

Check the picture below.

8 0
3 years ago
Find the area of a quadrilateral ABCD in which AB = 3 cm, BC = 4 cm, CD = 4 cm, DA = 5 cm and AC = 5 cm.
melamori03 [73]

Answer:

6+2\sqrt{21}\:\mathrm{cm^2}\approx 15.17\:\mathrm{cm^2}

Step-by-step explanation:

The quadrilateral ABCD consists of two triangles. By adding the area of the two triangles, we get the area of the entire quadrilateral.

Vertices A, B, and C form a right triangle with legs AB=3, BC=4, and AC=5. The two legs, 3 and 4, represent the triangle's height and base, respectively.

The area of a triangle with base b and height h is given by A=\frac{1}{2}bh. Therefore, the area of this right triangle is:

A=\frac{1}{2}\cdot 3\cdot 4=\frac{1}{2}\cdot 12=6\:\mathrm{cm^2}

The other triangle is a bit trickier. Triangle \triangle ADC is an isosceles triangles with sides 5, 5, and 4. To find its area, we can use Heron's Formula, given by:

A=\sqrt{s(s-a)(s-b)(s-c)}, where a, b, and c are three sides of the triangle and s is the semi-perimeter (s=\frac{a+b+c}{2}).

The semi-perimeter, s, is:

s=\frac{5+5+4}{2}=\frac{14}{2}=7

Therefore, the area of the isosceles triangle is:

A=\sqrt{7(7-5)(7-5)(7-4)},\\A=\sqrt{7\cdot 2\cdot 2\cdot 3},\\A=\sqrt{84}, \\A=2\sqrt{21}\:\mathrm{cm^2}

Thus, the area of the quadrilateral is:

6\:\mathrm{cm^2}+2\sqrt{21}\:\mathrm{cm^2}=\boxed{6+2\sqrt{21}\:\mathrm{cm^2}}

4 0
3 years ago
a student earned a grade of 80% on a math test that had 25 problems. how many problems on this test did the student answer corre
Mamont248 [21]
80% of 25
percent means parts out of 100
'of' means multiply
80% of 25 means
80/100 times 25=40/50 times 25=20/25 times 25=20

answer is 20 problems
6 0
3 years ago
Read 2 more answers
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