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vlada-n [284]
3 years ago
6

Convert each of the measurements given to the new unit stated using the factor label method (dimensional analysis). Show all wor

k including rewriting the given.
One step conversions:

26 cm to m ___________
4 hr to min ___________
3.25 km to m ___________
5 ft to in ___________
Chemistry
1 answer:
Diano4ka-milaya [45]3 years ago
3 0

26 cm -0.26 m

4 hr - 240 min

3.25 km -3250 m

5 ft -60 inches

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when 45 grams of copper (ii) carbonate are decomposed with heat how many grams of carbon dioxide will be produced
Maksim231197 [3]

Answer:

16.02 g

Explanation:

the balanced equation for the decomposition of CuCO₃ is as follows

CuCO₃ --> CuO + CO₂

molar ratio of CuCO₃ to CO₂ is 1:1

number of CuCO₃ moles decomposed - 45 g / 123.5 g/mol = 0.364 mol

according to the molar ratio

1 mol of CuCO₃ decomposes to form 1 mol of CO₂

therefore 0.364 mol of  CuCO₃ decomposes to form 0.364 mol of CO₂

number of CO₂ moles produced - 0.364 mol

therefore mass of CO₂ produced - 0.364 mol x 44 g/mol = 16.02 g

16.02 g of CO₂ produced

8 0
4 years ago
Why do actinides form covalent bond?​
Jet001 [13]

Answer:

bonding driven by ionic interactions.

Explanation:

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What is the formula for the polyatomic ion and name the following compound<br>Sn(NO2)2​
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A mixture of 0.600 mol of bromine and 1.600 mol of iodine is placed into a rigid 1.000-L container at 350°C.
kaheart [24]

The equilibrium constant of the reaction is 282. Option D

<h3>What is equilibrium constant?</h3>

The term equilibrium constant refers to the number that often depict how much the process is able to turn the reactants in to products. In other words, if the reactants are readily turned into products, then it follows that the equilibrium constant will be large and positive.

Concentration of bromine = 0.600 mol /1.000-L = 0.600 M

Concentration of iodine = 1.600 mol/1.000-L =  1.600M

In this case, we must set up the ICE table as shown;

              Br2(g) + I2(g) ↔ 2IBr(g)

I          0.6            1.6           0

C      -x                -x             +2x

E    0.6 - x         1.6 - x       1.190

If 2x = 1.190

x = 1.190/2

x = 0.595

The concentrations at equilibrium are;

[Br2] = 0.6 -  0.595 = 0.005

[I2] =   1.6 - 0.595 = 1.005

Hence;

Kc = [IBr]^2/[Br2] [I2]

Kc = ( 1.190)^2/(0.005) (1.005)

Kc = 282

Learn more about equilibrium constant:brainly.com/question/15118952

#SPJ1

4 0
2 years ago
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