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svp [43]
3 years ago
9

Helium is commonly used in balloons because it is lighter than air. It was first discovered by ___________ in the year _________

___.
Also giving brainiest whoever answers right :)
Chemistry
2 answers:
Elza [17]3 years ago
7 0
It was discovered in 1868 ;)
Sidana [21]3 years ago
5 0

Answer: Discovered by William Ramsay

Discovered in 1868

Explanation:

You might be interested in
What is the Law of Conservation of Mass/Matter?
Ostrovityanka [42]

Answer:

O Mass/Matter cannot be created or destroyed

8 0
3 years ago
5.54 moles of AgNO3 are dissolved in 0.48 L of water. What is the molarity of the AgNO, solution?
expeople1 [14]

Answer:

11.54 M

Explanation:

In this case, all we have to do is to apply the following expression:

M = n/V

M: molarity

n: moles

V: volume of solution in liters

In this case, we can assume that the volume of water will be the volume of solution. This is because the problem is not specifing if the moles of AgNO3 are liquid or solid, so we can make a safe assumption of the volume.

Using the expression above we have:

M = 5.54 / 0.48

M = 11.54 M

This is the molarity of solution

7 0
4 years ago
Read 2 more answers
f 65mL of sulfuric acid and 25mL of sodium hydroxide were mixed and the solution had a density of 1.01g/mL, what is the heat of
user100 [1]

The question is incomplete, here is the complete question:

If 65 mL of sulfuric acid and 25 mL of sodium hydroxide were mixed and the solution had a density of 1.01 g/mL, What is the heat of the calorimeter in kJ given the temperature change of the above equation is -5.5 K. You may assume the solution has a heat capacity of 4.180 J/gK. Express your final answer in kJ and with 2 decimal places

<u>Answer:</u> The heat of the calorimeter is 2.09 kJ

<u>Explanation:</u>

To calculate the mass of solution, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

Density of solution = 1.01 g/mL

Volume of solution = [65 + 25] mL = 90 mL

Putting values in above equation, we get:

1.01g/mL=\frac{\text{Mass of solution}}{90mL}\\\\\text{Mass of solution}=(1.01g/mL\times 90mL)=90.9g

To calculate the heat released by the reaction, we use the equation:

q=mc\Delta T

where,

q = heat released

m = mass of solution = 90.9 g

c = heat capacity of solution = 4.180 J/g.K

\Delta T = change in temperature = -5.5 K

Putting values in above equation, we get:

q=90.9g\times 4.180J/g.K\times (-5.5K)=-2089.8J=-2.09kJ

Heat released by the solution will be equal to the heat absorbed by the calorimeter.

<u>Sign convention of heat:</u>

When heat is absorbed, the sign of heat is taken to be positive and when heat is released, the sign of heat is taken to be negative.

Heat absorbed by the calorimeter = -(-2.09) = 2.09 kJ

Hence, the heat of the calorimeter is 2.09 kJ

8 0
4 years ago
Gaseous indium dihydride is formed from the elements at elevated temperature:
3241004551 [841]

<u>Answer:</u>

<u>For 1:</u> The value of Q_p for above reaction is 36.83

<u>For 2:</u> The value of Q_p for above reaction is 36.83

<u>For 3:</u> The equilibrium partial pressure of Indium is 0.126 atm

<u>For 4:</u> The equilibrium partial pressure of hydrogen gas is 0.094 atm

<u>For 5:</u> The equilibrium partial pressure of Indium dihydrogen is 0.018 atm

<u>Explanation:</u>

We are given:

Partial pressure of Indium gas = 0.0650 atm

Partial pressure of hydrogen gas = 0.0330 atm

Partial pressure of Indium dihydride = 0.0790 atm

The given chemical equation follows:

                      ln(g)+H_2(g)\rightleftharpoons InH_2(g)

<u>Initial:</u>               0.065     0.033           0.079

<u>At eqllm:</u>       0.065-x   0.033-x       0.079+x

  • <u>For 1:</u>

The expression of Q_p for above reaction follows:

Q_p=\frac{p_{InH_2}}{p_{In}\times p_{H_2}}

Putting values in above equation, we get:

Q_p=\frac{0.079}{0.065\times 0.033}=36.83

Hence, the value of Q_p for above reaction is 36.83

  • <u>For 2:</u>

We are given:

K_p of the reaction = 1.48

There are 3 conditions:

  • When K_{p}>Q_p; the reaction is product favored.
  • When K_{p}; the reaction is reactant favored.
  • When K_{p}=Q_p; the reaction is in equilibrium.

As, Q_{p}>K_p for the given reaction, the reaction is reactant favored.

Hence, the reaction proceed in the backward direction to attain equilibrium

  • <u>For 3:</u>

The expression of K_p for above reaction follows:

K_p=\frac{p_{InH_2}}{p_{In}\times p_{H_2}}

Putting values in above equation, we get:

1.48=\frac{(0.079+x)}{(0.065-x)\times (0.033-x)}\\\\x=-0.061,0.835

Neglecting the value of x = 0.835 because the reaction is going backwards. So, by taking this value, the pressure of the reactants will decrease

So, equilibrium partial pressure of Indium = (0.065 - x) = [0.065 - (-0.061)] = 0.126 atm

  • <u>For 4:</u>

The equilibrium partial pressure of hydrogen gas = (0.033 - x) = [0.033 - (-0.061)] = 0.094 atm

  • <u>For 5:</u>

The equilibrium partial pressure of Indium dihydrogen = (0.079 + x) = [0.079 + (-0.061)] = 0.018 atm

6 0
3 years ago
How much heat is released when 47.50 g of CH4 (g) is burned in excess oxygen gas to produce carbon dioxide and water?
Elina [12.6K]

Answer:

= 2113.44 kJ

Explanation:

When 1 mole of CH4 (g) burns in excess oxygen -714.0 kJ of heat is released.

For 47.50 g;

molar mass of CH4 = 16.042 g/mol

Number of moles of CH4

   = 47.5 g /16.042 g/mol

   = 2.96 moles

Therefore;

1 mole = -714.0 kJ

Heat change for 2.96 moles

 = 2.96 moles × -714.0 kJ

 = 2113.44 kJ

8 0
3 years ago
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