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svp [43]
3 years ago
9

Helium is commonly used in balloons because it is lighter than air. It was first discovered by ___________ in the year _________

___.
Also giving brainiest whoever answers right :)
Chemistry
2 answers:
Elza [17]3 years ago
7 0
It was discovered in 1868 ;)
Sidana [21]3 years ago
5 0

Answer: Discovered by William Ramsay

Discovered in 1868

Explanation:

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How does water’s high specific heat capacity affect large lakes?
telo118 [61]

Answer:

the water in a lake changes temperature slowly

Explanation:

the higher the specific heat capacity the more heat can be absorbed so a large lake can absorb a large amount of heat without increasing the temperature much

5 0
3 years ago
Read 2 more answers
Why is energy required for the boiling process?
-Dominant- [34]
The heat is the required energy.
5 0
3 years ago
Which of the following statements is true?
Ivahew [28]
I believe the answer would be D.
5 0
4 years ago
Solutions of mercury (I) nitrate and potassium bromide are mixed
Afina-wow [57]
With that informatio you can:

1) Write the chemical equation
2) Balance the chemical equation
3) State the molar ratios
4) Predict if precipitation occurs.

I will do all four, for you:

1) Chemical equation:

mercury(I) nitrate  potassium bromide    mercury(I) bromide  potassium nitrate
<span>Hg2(NO3)2             +        KBr                   → Hg2Br2          +      KNO<span>3

2) Balanced chemical equation
</span></span>
<span>Hg2(NO3)2 + 2KBr → Hg2Br2 + 2KNO<span>3

3) Molar ratios or proportions:

1 mol </span></span><span>Hg2(NO3)2 : 2 mol KBr : 1 mol Hg2Br2 : 2 mol KNO<span>3

4) Prediction of precipitation.

You can use the solubility rules or a table of solubilities. I found in a table of solutiblities that mercury(I) bromide is insoluble and potassium bromide is soluble, Then you can predict that the precipitation of mercury(I) bromide will occur.


</span></span>
7 0
3 years ago
If 1495 J of heat is needed to raise the temperature of a 319 g sample of a metal from 55.0°C to 66.0°C, what is the specific he
Olegator [25]
The specific  heat  capacity  of the  metal  is calculated  using  the  following  formula
Q(heat)= MC delta T
Q= 1495 j
c= specific heat   capacity =?
M(mass)=319 g
delta T = change  in  temperature = 66-55 =11 c
by  making   c  the subject  of the formula 

  C=Q /M delta T
c= 1495 j/ 319 g  x 11 c =0.426 j/g/c

3 0
3 years ago
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