To determine the voltage of the battery above, we use Ohm's Law which relates voltage (V), current (I) and resistance (R) in a circuit. It is expressed as V = IR. We calculate as follows:
V = IR
V = .43 A ( 3.5 ohms )
V = 1.505 V
Therefore, the correct answer is option A.
So, the equation NaCl is a 1:1 mol ratio, so we need to convert grams of Na to mols of Na. Then we take that mols of Na, and then since it is a 1:1 ratio, it is the same number of mols of Cl. Then, we take the mols of Cl and multiply it by the mol ratio.
The equation looks as the following:
So, 53.99260 is the answer, but rounding to sig figs, we round to 3 sig figs (since 35.0 has only 3 sig figs)
54.0g Cl