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masya89 [10]
3 years ago
9

Does anyone know the answer to this chemistry question?!?

Chemistry
1 answer:
Pepsi [2]3 years ago
7 0

Answer:

Mass of HCl = 73 g

Explanation:

Given data:

Mass of hydrogen = 2 g

Mass of HCl = ?

Solution:

First of all we will write the balance chemical equation:

H₂ + Cl₂   →  2HCl

Number of moles of hydrogen = 2 g/ 2g/mol

Number of moles of hydrogen = 1 mol

Form balanced chemical equation compare the moles hydrogen with HCl.

                   H₂    :   HCl

                    1      :    2

Mass of HCl:

Mass of HCl = number of moles × molar mass

Mass of HCl = 2 mol × 36.5 g/mol

Mass of HCl = 73 g

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Sloan [31]

Answer:

The correct answer to the following question will be "4.08 × 10⁻¹⁹ Joule".

Explanation:

Given:

Wavelength, λ = 486.0 nm

As we know,

E=h\upsilon =\frac{hc}{\lambda}

On putting the estimated values, we get

⇒          =\frac{1241.5 \ ev\ nm}{486 \ nm}

⇒          =2.554 \ ev

∴ 1 ev = 1.6 × 10⁻¹⁹ J

Now,

Energy, E=2.554\times 1.6\times 10^{-19}

⇒               =4.08\times 10^{-19} Joule

7 0
3 years ago
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D. Ba and F. Took the test
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the radius of magnesium atom is 0.160nm. the radius of a magnesium ion is 7.2x 10^-11m. explain the difference in size between t
Allushta [10]

Answer:

during reaction magnesium lises ions.

Explanation:

magnesium reacts by losing two ions which makes it smaller in size.

8 0
3 years ago
Select the compound that is most likely to increase the solubility of ZnSe when added to water.NaCnMgBr2NaClKClO4
vlada-n [284]

Answer:

NaCl.

Explanation:

In the solution, ZnSe ionizes to Zn^2^+ and Se^2^- . Following reaction represents the ionization of ZnSe in solution -

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As we want to increase the solubility of ZnSe, we must decrease the concentration of dissociated ions so that the reaction continues to forward direction.

If we add NaCl to this solution, then we have Na^+ and Cl^- in the solution which will be formed by the ionization of NaCl.

Now, Zn^2^+ in the solution will react with two Cl^- ions to form ZnCl_2 as follows -

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Due to this reaction the concentration of Zn^2^+ will decrease in the solution and more ZnSe can be soluble in the solution.

6 0
3 years ago
What is the [OH-] in a solution with a poh of 3.90
zheka24 [161]

Answer:

7.9433E-3

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=7.9433×10^-3

8 0
3 years ago
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