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3 years ago

What are the magnitude forces at C and D? Please help

Physics

1 answer:

Anastasy [175]3 years ago

4 0

Answer:

Explanation:

Beacuse the force got to the bottem first Meaning the andswer is D

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Are we really real or are we all an allusion?Do you believe in past lives?How do you think you died in past life?

OLEGan [10]

Answer:

I don't even know

Explanation:

Shower thoughts

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3 years ago

Read 2 more answers

A person eats a container of strawberry yogurt. The Nutritional Facts label states that it contains 255 Calories (1 Calorie = 41

Sever21 [200]

Answer:

mass = 0.44 Kg

Explanation:

given,

Calories contain in the strawberry yogurt = 255 calories

1 Calorie = 4186 J

latent heat of vaporization = 2.42 x 10⁶ J/Kg

mass of perspiration = ?

Energy = 255 calories

Energy = 255 x 4186

= 1067430 J

Energy = mass x latent heat of vaporization

$mass = \dfrac{Q}{L_v}$

$mass = \dfrac{1067430}{2.42 \times 10^6}$

mass = 0.44 Kg

4 0

4 years ago

The cylindrical head bolts on a car are to be tightened with a torque of 63.3 N · m. If a mechanic uses a wrench of length 18.2

Nataly_w [17]

Answer: The perpendicular force to be used to tighten the bolt is

F=347.8N

Explanation:

Mathematically the torque is expressed as

T=F*L

Where T= torque in Nm

F= force in N

And L = perpendicular distance

Now given

T=63.3Nm

L=18.2cm to meter 18.2/100

0.182m

F=?

Making F the subject of the formula in our equation

F=T/L

F=63.3/0.182

F=347.8N

What is torque?

Torque is the product of force and perpendicular distance of the line of action.

6 0

4 years ago

A 26.0 g ball is fired horizontally with initial speed v0 toward a 110 g ball that is hanging motionless from a 1.10 m -long str

mart [117]

Answer:

$7.3 ms^{-1}$

Explanation:

Consider the motion of the ball attached to string.

In triangle ABD

$Cos50 = \frac{AB}{AD} \\Cos50 = \frac{AB}{L}\\AB = L Cos50$

height gained by the ball is given as

$h = BC = AC - AD \\h = L - L Cos50\\h = 1.10 - 1.10 Cos50\\h = 0.393 m$

$M$ = mass of the ball attached to string = 110 g

$V$ = speed of the ball attached to string just after collision

Using conservation of energy

Potential energy gained = Kinetic energy lost

$Mgh = (0.5) M V^{2} \\V = sqrt(2gh)\\V = sqrt(2(9.8)(0.393))\\V = 2.8 ms^{-1}$

Consider the collision between the two balls

$m$ = mass of the ball fired = 26 g

$v_{o}$ = initial velocity of ball fired before collision = ?

$v_{f}$ = final velocity of ball fired after collision = ?

using conservation of momentum

$m v_{o} = MV + m v_{f}\\26 v_{o} = (110)(2.8) + 26 v_{f}\\v_{f} = v_{o} - 11.85$

Using conservation of kinetic energy

$m v_{o}^{2} = MV^{2} + m v_{f}^{2} \\26 v_{o}^{2} = 110 (2.8)^{2} + 26 (v_{o} - 11.85)^{2} \\v_{o} = 7.3 ms^{-1}$

3 0

3 years ago

In which surface does the toy car move easily or fast?why?

statuscvo [17]

sandpaper and gravel surface

8 0

3 years ago