In which surface does the toy car move easily or fast?why?

The coefficient of kinetic friction for a 22 kg bobsled on a track is 0.10. What force is required to push it down a 5.0 degree

frosja888 [35]

Hi there!

We must begin by converting km/h to m/s using dimensional analysis:

$\frac{62km}{1hr} * \frac{1hr}{3600sec}*\frac{1000m}{1km} = 17.22 m/s$

Now, we can use the kinematic equation below to find the required acceleration:

vf² = vi² + 2ad

We can assume the object starts from rest, so:

vf² = 2ad

(17.22)²/(2 · 75) = a

a = 1.978 m/s²

Now, we can begin looking at forces.

For an object moving down a ramp experiencing friction and an applied force, we have the forces:

Fκ = μMgcosθ = Force due to kinetic friction

Mgsinθ = Force due to gravity

A = Applied Force

We can write out the summation. Let down the incline be positive.

ΣF = A + Mgsinθ - μMgcosθ

Or:

ma = A + Mgsinθ - μMgcosθ

We can plug in the given values:

22(1.978) = A + 22(9.8sin(5)) - 0.10(22 · 9.8cos(5))

A = 46.203 N

6 0

3 years ago

What is the energy stored between 2 Carbon nuclei that are 1.00 nm apart from each other? HINT: Carbon nuclei have 6 protons and

Andrei [34K]

Answer:

$A. 8.29\times 10^{-18}\ J$

Explanation:

Given that:

p = magnitude of charge on a proton = $1.6\times 10^{-19}\ C$

k = Boltzmann constant = $9\times 10^{9}\ Nm^2/C^2$

r = distance between the two carbon nuclei = 1.00 nm = $1.00\times 10^{-9}\ m$

Since a carbon nucleus contains 6 protons.

So, charge on a carbon nucleus is $q = 6p=6\times 1.6\times 10^{-19}\ C=9.6\times 10^{-19}\ C$

We know that the electric potential energy between two charges q and Q separated by a distance r is given by:

$U = \dfrac{kQq}{r}$

So, the potential energy between the two nuclei of carbon is as below:

$U= \dfrac{kqq}{r}\\\Rightarrow U = \dfrac{kq^2}{r}\\\Rightarrow U = \dfrac{9\times10^9\times (9.6\times 10^{-19})^2}{1.0\times 10^{-9}}\\\Rightarrow U =8.29\times 10^{-18}\ J$

Hence, the energy stored between two nuclei of carbon is $8.29\times 10^{-18}\ J$ .

8 0

3 years ago

Increasing the concentration and increasing the temperature both increase reaction rates based on which physical phenomenon? 1.

vekshin1

You can deal with this question using the collision theory, which states that the chemical reactions occur when particles collide with enough energy to reach the Activation Energy.

The velocity of the particles is related with the temperature. At higher temperatures, higher velocities and higher frequency of collisions.

Also, at higher concentration (more particles is a same volume) the number of collisions will increase.

Then, hIgher concentration and higher temperature will increase the frequency of the molecular collisions..

Then, the answer is the proposal #1: "<span>increasing the frequency of molecular collisions"</span>

5 0

3 years ago

Read 2 more answers

If you have a density of 100kg/L and a mass of 1000 units, tell me the following: second what is the volume

adell [148]

Answer:

volume is 0.1 L

Explanation:

you can use the equation density=mass/volume

100 = 1000 / v

divide by 1000 on both sides

0.1 = v

8 0

3 years ago

Suppose a vacuum cleaner uses 120 J of electrical energy is 45 J are used to pull air into the vacuum cleaner how efficient is t

Airida [17]

Very efficient because it uses less then half to do the action then the vacuum actually stores.

3 0

4 years ago

In which surface does the toy car move easily or fast?why?​

In which surface does the toy car move easily or fast?why?