Answer:

Explanation:
Given data:



Let the distance traveled by the object in the second case be 
In the given problem, work done by the forces are same in both the cases.
Thus,





Answer:
The gravitational potential energy of a squirrel is 53.312 J.
Explanation:
We have,
Mass of a squirrel is 0.68 kg
It is placed at a height of 8 m above the ground.
It is required to find the gravitational potential energy of a squirrel. It is possessed by an object due to its position. Its formula is given by :

So, the gravitational potential energy of a squirrel is 53.312 J.
The force of impact is same for both bus and the bicycle. The acceleration of bicycle will be greater than the acceleration of bus.
<u>Explanation:</u>
The interaction that occurs between two objects refers to collision. this makes the two objects to come in contact with each other. The third law of Newton states that, when there occurs a collision between two objects, then the force that is applied on each object will be same. But, the direct in which the force is impacted will be in opposite direction.
The magnitude of the forces will be equal but the direction will not be same. The collision results in gaining the momentum by one object and losing momentum by another. The acceleration is mainly associated with the mass of the object. When the object has smaller mass, it will be accelerated more. In the given example, as bus is heavier than bicycle, the bicycle will have greater acceleration than the bus.
Answer:
exercise can lower levels
You told your insane friend that it will take the book 5.6 s to get to the ground.
From the question given above, the following data were obtained:
Height (H) = 155 m
<h3>Time (t) =? </h3>
<u>NOTE</u>: Acceleration due to gravity (g) = 10 m/s²
The time taken for the book to get to ground can be obtained as follow:
<h3>H = ½gt²</h3>
155 = ½ × 10 × t²
155 = 5 × t²
<h3>Divide both side by 5</h3>

t² = 31
<h3>Take the square root of both side </h3>

<h3>t = 5.6 s</h3>
Thus, the time taken for the book to get to the ground is 5.6 s
Hence, you told your insane friend that it will take the book 5.6 s to get to the ground.
Learn more: brainly.com/question/24903556