Explanation:
Pressure is the same for both plungers.
P = P
F / A = F / A
F / (¼ π d²) = F / (¼ π d²)
F / d² = F / d²
5 N / (0.05 m)² = F / (1 m)²
F = 2000 N
None of the options are correct.
Answer:
South = 1.5m
West =4.2m
Explanation:
Kindly see attached a rough draft of the situation
Step one
Given data
From the sketch the direction of the player is along the resultant of the triangle, corresponding to the Hypotenuse
Step two:
Hence for an opponent to tackle him towards the south, he must be at
sin θ= opp/hyp
sin 20=x/4.5
x=sin 20*4.5
x=0.342*4.5
x= 1.5m
Also, for an opponent to tackle him towards the south, he must be at
cos θ= adj/hyp
cos 20=y/4.5
y=cos 20*4.5
y=0.93*4.5
y= 4.2m
The type of graph that would most appropriately display Sarah's data is a line graph.
<h3>What is a line graph?</h3>
A line graph, sometimes referred to as a line plot or a line chart, is a graph in which individual data points are connected by lines. A line graph shows numerical values over a predetermined period of time.
Line graphs are frequently used in finance to show the historical price movement of an asset or instrument. To monitor changes over both short and long time periods, line graphs are utilized. Line graphs can be used to compare changes for multiple groups over the same time period.
In this case, it should be noted that Sarah wants to compare the speed and the height. Therefore, the line graph and s appropriate.
Learn more about graph on:
brainly.com/question/19040584
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<h2>Answer</h2>
1m/s
<h2>Explanation</h2>
Given that:
<em>Mass of first blob = 2kg = m1</em>
<em>Velocity of blob = 4m/s = v1</em>
<em>Mass of second blob = 6kg = m2</em>
<em>Velocity of blob = 0m/s = v2</em>
<em />
To find:
<em>Final velocity = Vf</em>
<em />
<em>This question is of inelastic collision which is any collision between objects in which some energy is lost.</em>
<em />
<h3>Formula to be use:</h3><h2>(m1*v1) + (m2*V2) = Vf(m1 + m2)</h2>
(2*4) + (6*0) = Vf(2+6)
8 + 0 = Vf(8)
8 = Vf(8)
Vf = 1 m/s
So the speed of two blobs immediately after colliding = 1 m/s
Answer : 63 km/h
Explanation :
Outgoing distance = 300 km.
Outgoing speed = 93 km/h.
Break time = 1 h
Return distance = 300 km
Return speed = 56 km/h
Outgoing time = outgoing distance / outgoing speed
Outgoing time = 300 km / 93 km/h = 3.225806451612 h
Return time = return distance / return speed
Return time = 300 km / 56 km/h = 5.357142867142 h
Total distance =. Outgoing distance + return distance travelled
Total distance = 300 km + 300 km = 600 km
Total time = outgoing time + break time + return time
Total time = 3.225806451612 h + 1 h+ 5. 357142867142 h = 9.582949308754 h
Average speed = total distance / total time
Average speed = 600 km / 9.582949308754 h
Average speed = 62.61120462042 km/h = 63 km/h
