Answer: The multiplicative inverse is 1/2 the addition inverse is -2
Step-by-step explanation:
Since the inverse of multiplication is division, use a fraction. The inverse of addition is subtraction.
Answer:
y=1/4x-2
Step-by-step explanation:
the first y axis number it touches is -2 and the slope is 1/4.
Let's call that number x, twice the number will be 2x, sum of it and 5 is, 2x+5. So if this expression is at most 15, it means, it can be only less than 15 and equal to 15. Let's show this as an inequality.

Let's solve.

![x\quad \in \quad \left[ -\infty ,5 \right]](https://tex.z-dn.net/?f=x%5Cquad%20%5Cin%20%5Cquad%20%5Cleft%5B%20-%5Cinfty%20%2C5%20%5Cright%5D%20)
If the number is a natural number. The values it can take is,
Answer:
a) 131/450
b) 1233/1276
Step-by-step explanation:
P(bad) = P(1st batch)*P(bad 1st batch ) + P(2nd batch )*P(bad 2nd batch) + P(3rd batch )*P(bad 3rd batch)
p(bad) =(60/360)*(1/3) + (120/360)*(1/4 ) + (180/360)*(1/5)
= 43/180
And that of P(good )
= 1 - 43/180
= 137/180
a)
P(defective) = P(bad)*P(defective /bad) + P(good)*P(defective /good)
= (43/180)*(9/10) + (137/180)*(1/10)
= 131/450
b)
P(Bc I Dc ) = P(good)*P(not defective |good) / P(not defective)
= (137/180)*(1 - 1/10) / (1 - 131/450)
= 1233/1276
Answer:
6 apples, 21 apples, 30 apples respectively
Step-by-step explanation:
Let us first start by writing <u>expressions</u> so that we can easily solve for the problems below.
Let us suppose Alice is x. In this case, Claire has 3 times Alice's apples, so 3x.
1. If Alice has 2 apples (x), then Claire has 3x
3*2=<u>6 apples</u>
Claire has 6 apples.
2. If Alice has 7 apples (x), then Claire has 3x
3*7=<u>21 apples</u>
Claire has 21 apples.
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3. If Alice has 10 apples (x), then Claire has 3x
3*10=<u>30 apples</u>
Claire has 30 apples.
<em>I hope this helps! Please let me know if you have any further questions :)</em>