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3 years ago

Suppose that G(x) = F(x + 9). Which statement best compares the graph of

Mathematics

1 answer:

Charra [1.4K]3 years ago

3 0

C. The graph of G(x) is the graph of F(x) shifted 9 units to the left.

Inside changes do the opposite of what they seem like they'd do. "x+9" shifts it left 9 units.

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Write each rate as a unit rate. $2 for 5 cans of soup.

Len [333]

If you would like to write each rate as a unit rate, you can do this using the following steps:

$2 ... 5 cans of a soup
$1 ... x cans of a soup = ?

2 * x = 5 * 1
2 * x = 5
x = 5 / 2
x = 2.5 cans of a soup per $1

$2 ... 5 cans of a soup
$x = ? ... 1 can of a soup

2 * 1 = 5 * x
2 = 5 * x
x = 2 / 5
x = $0.4 per 1 can of a soup

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3 years ago

H(x) = x2 1 k(x) = x – 2 (h k)(2) = (h – k)(3) = Evaluate 3h(2) 2k(3) =.

natima [27]

Quadratic equation is the equation in which only one variable is unknown. The highest power of the variable is 2.The value of the given functions are,

$(h+k)(x)=5$

$(h-k)(x)=9$

$3h(2)+2k(3)=17$

<h3>Given information-</h3>

The given function is,

$h(x)=x^2+1$

$k(x)=x-2$

<h3>Quadratic equation</h3>

Quadratic equation is the equation in which only one variable is unknown. The highest power of the variable is 2.

1) The value of the function (h+k)(2),

$(h+k)(x)=h(x)+k(x)$

$(h+k)(x)=x^2+1+x-2$

$(h+k)(2)=2^2+1+2-2$

$(h+k)(x)=5$

2)The value of the function (h-k)(3),

$(h-k)(x)=h(x)-k(x)$

$(h-k)(x)=x^2+1-x+2$

$(h-k)(3)=3^2+1-3+2$

$(h-k)(x)=9$

3) The value of the function 3h(2)+2k(3)

$3h(x)+2k(x)=3x^2+3+2x-2\times 2$

$3h(2)+2k(3)=3\times2^2+3+2\times2-2\times 2$

$3h(2)+2k(3)=17$

Hence the value of the given functions are,

$(h+k)(x)=5$

$(h-k)(x)=9$

$3h(2)+2k(3)=17$

Learn more about the quadratic equation here;

brainly.com/question/2263981

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3 years ago

HEEEEEEEEEEELP MEEEEEEEEEEE

Diano4ka-milaya [45]

Answer: of ok

Step-by-step explanation:

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3 years ago

A rectangular park has a width of 8/9 of a mile and a length 3/5 of a mile. Find the

Nesterboy [21]

Answer:0.53 miles

Step-by-step explanation:

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3 years ago

the Honda CRV gets 37 miles per gallon on average how much carbon dioxide will be admitted if the Honda were driven 400 miles

Pani-rosa [81]

According to the equation located here: https://www.1728.org/glwarmng.htm burning one gallon of gasoline produces 19.3 pounds of carbon dioxide.

So, if a car gets 37 miles per gallon and if it travels 400 miles, it will use 10.81 gallons of gasoline and will produce 19.3 * 10.81 = 208.63 pounds of carbon dioxide.

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4 years ago