If R is the midpoint of QS,QR=5x-4 and RS=2x+2,find QS
1 answer:
You might be interested in
Answer:
They are not perpendicular because their slopes are not negative reciprocals.
Step-by-step explanation:
Well first we need to find slope.
Line HJ)
(-4,-2) , (0,4)
y2 is 4 y1 is -2, so 4 - -2 = 6
0 - -4 = 4
6/4 -> 3/2
Due to the point (0,4) having no x value 4 is the y intercept.
Hence, y = 3/2x + 4 is the slope of line HJ
Line FG)
(-4,1) , (0,-2)
y2 is -2 y1 is 1, so -2 - 1 = -3
0- -4 = 4
Because (0,-2) is missing an x value -2 is the y intercept,
Equation: y = -3/4x - 2
They are not perpendicular because their slopes are not negative reciprocals.
