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OverLord2011 [107]
2 years ago
6

Identify Label these cell parts

Physics
2 answers:
Kruka [31]2 years ago
8 0

Answer:

I don't know this answer because I am not American

navik [9.2K]2 years ago
6 0
I would say nucleus I’m not so sorry
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A bulb pile is driven to the ground with a 2.5 ton hammer. The drop height is 22 ft and the volume in last batch driven is 4 cu
Stels [109]

Answer:

159.1 ton

Explanation:

The solution is shown in the attached file

Download docx
5 0
3 years ago
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If a 20 g cannonball is shot from a 5 kg cannon with a velocity of 100
balu736 [363]

Strange as it may seem, the statement in the question appears to be <em>TRUE</em>.  

-- Before the shot, neither the cannon nor the ball is moving, so their combined momentum is zero.  

-- Since momentum is conserved, we know immediately that their combined momentum AFTER the shot also has to be zero.

-- (20g is rather puny for a "cannonball" ... about the same weight as four nickels. But we'll take your word for it and just do the Math and the Physics.)

-- Momentum = (mass) x (velocity)

After the shot, the momentum of the cannonball is

(0.02 kg) x (100 m/s ==> that way)

Momentum of the ball = 2 kg-m/s ==> that way.

-- In order for both of them to add up to zero, the momentum of the cannon must be (2 kg-m/s this way <==) .

Momentum of cannon = (5 kg) x (V m/s this way <==)

2 kg-m/s this way <== = (5 kg) x (V m/s this way <==)

Divide each side by (5 kg):

V m/s  =  (2/5) m/s this way <==

Speed of recoil of the cannon = <em>-- 0.4 m/s</em>

3 0
3 years ago
What is a force field
amid [387]
Chiefly in science fiction) an invisible barrier of exerted strength or impetus.
3 0
3 years ago
John had a stroke and is having difficulty sitting and walking. Which medical professional should he consult to improve his phys
slava [35]
John needs to see a physical therapist because he cannot walk very well.
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3 years ago
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A step index fiber has a numerical aperture of NA = 0.1. The refractive index of its cladding is 1.465. What is the largest core
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Answer:

diameter = 9.951 × 10^{-6} m

Explanation:

given data

NA = 0.1

refractive index = 1.465

wavelength = 1.3 μm

to find out

What is the largest core diameter for which the fiber remains single-mode

solution

we know that for single mode v number is

V ≤ 2.405

and v = \frac{2*\pi *r}{ wavelength} NA

here r is radius    

so we can say

\frac{2*\pi *r}{ wavelength} NA    = 2.405

put here value

\frac{2*\pi *r}{1.3*10^{-6}} 0.1    = 2.405

solve it we get r

r = 4.975979 × x^{-6} m

so diameter is = 2  ×  4.975979 × 10^{-6} m

diameter = 9.951 × 10^{-6} m

3 0
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