B. NaCl
All of the other answers contain a 2 or a number in general. Metals do not form covalent bonds. Alkali-halide salts are Ionic compounds. Ionic compounds form from bonding a metal and a non metal. Covalent bonds are formed by bonding non metals.
Answer:
rate of infusion is 900 mL/hr
Explanation:
given data
Infuse I1 = 1000 mL
delivers = 15 gtt/mL
Infuse I2 = 300 mL
time t= 20 min
rate = 60 mL/hr
to find out
rate of infusion
solution
we know here we give 300 mL infuse in 20 min
so here for 20 min
rate of infusion is express as
rate of infusion = I2 / t
rate of infusion = 300 / 20
rate of infusion = 15 mL / min
rate of infusion = 15 × 60 = 900
so rate of infusion is 900 mL/hr
The kind of equation that can be used to differentiate the kind of separatrix that shows change on motion is
H = 2g/l.
<h3>What is simple pendulum?</h3>
A simple pendulum can be defined as the equipment that displays an oscillatory motion when a mass is tied on a rope and is suspended from it.
The various movements that occur using a simple pendulum is translational ( side to side) or continuous circle (oscillatory motion).
The equation that show that a change from one type of motion to another is H = 2g/l.
Learn more about motion here:
brainly.com/question/453639
#SPJ1
Answer:
u/2 √(1 + 3 cos² θ)
Explanation:
The object is thrown at an angle θ, so the velocity has two components, vertical and horizontal.
Initially, the vertical component is u sin θ and the horizontal component is u cos θ.
At the maximum height, the vertical component is 0 and the horizontal component is u cos θ.
The mean vertical velocity is:
(u sin θ + 0) / 2 = u/2 sin θ
The mean horizontal velocity is:
(u cos θ + u cos θ) / 2 = u cos θ
The net mean velocity can be found with Pythagorean theorem:
v² = (u/2 sin θ)² + (u cos θ)²
v² = u²/4 sin² θ + u² cos² θ
v² = u²/4 (1 − cos² θ) + u² cos² θ
v² = u²/4 (1 − cos² θ) + u²/4 (4 cos² θ)
v² = u²/4 (1 − cos² θ + 4 cos² θ)
v² = u²/4 (1 + 3 cos² θ)
v = u/2 √(1 + 3 cos² θ)
Answer:
Correct answer: (a) Ekmax = 1.3 · 10⁻¹⁹ J, (b) ε = 5 eV, (c) f = 1.21 · 10¹⁵ Hz
Explanation:
Given:
photon energy ε = 8 · 10⁻¹⁹ J
work function for metal Wf = 6.7 · 10⁻¹⁹ J
(a) Ekmax = ?
The Einstein equation for photo effect is:
ε = Wf + Ekmax ⇒ Ekmax = ε - Wf
Ekmax = 8 · 10⁻¹⁹ - 6.7 · 10⁻¹⁹ = 1.3 · 10⁻¹⁹ J
Ekmax = 1.3 · 10⁻¹⁹ J
(b) ε = ? eV
the relationship between 1 eV and 1 J is:
1 eV = 1.6 · 10⁻¹⁹ J
so the energy of one photon in eV equals:
ε = 8 · 10⁻¹⁹ J = 8 · 10⁻¹⁹ / 1.6 · 10⁻¹⁹ eV = 5 eV
ε = 5 eV
(c) f = ?
the energy of a single photon is calculated according to the formula:
ε = h · f
where is:
h = 6.62 · 10⁻³⁴ J s plank constant
and f frequency of each photon (electromagnetic radiation)
f = ε / h = 8 · 10⁻¹⁹ J / 6.62 · 10⁻³⁴ J s = 1.21 · 10¹⁵ s⁻¹ = 1.21 · 10¹⁵ Hz
f = 1.21 · 10¹⁵ Hz
God is with you!!!