Headphones, refrigerator magnets, and compasses
Hope that was helpful.
Answer:
I= 3.5 amps
Explanation:
Step one:
given data
rating of resistor R= 8 ohms
power P= 100W
Required
The current I
Step two
Yet this power is also given by
![P = I^2R](https://tex.z-dn.net/?f=P%20%3D%20I%5E2R)
make I subject of the formula we have
![I= \sqrt{\frac{P}{R} }](https://tex.z-dn.net/?f=I%3D%20%5Csqrt%7B%5Cfrac%7BP%7D%7BR%7D%20%7D)
substitute
![I= \sqrt{\frac{100}{8} }\\\\I=\sqrt{12.5}\\\\I= 3.5 amps](https://tex.z-dn.net/?f=I%3D%20%5Csqrt%7B%5Cfrac%7B100%7D%7B8%7D%20%7D%5C%5C%5C%5CI%3D%5Csqrt%7B12.5%7D%5C%5C%5C%5CI%3D%203.5%20amps)
Answer:
a) 1450watts
b) 564watts
c) 1.11
Explanation:
Power consumed = IV
I is the current rating
V is the operating voltage
If a blow-dryer and a vacuum cleaner each operate with a voltage of 120 V and the current rating of the blow-dryer is 12 A, while that of the vacuum cleaner is 4.7 A then their individual power rating is calculated thus;
a) For blow-dryer
Operating voltage = 120V
Its current rating = 12A
Power consumed = IV
= 120×12
= 1440watts
b) For vacuum cleaner:
Operating voltage is the same as that of blow dryer = 120V
Its current rating = 4.7A
Power consumed = IV
= 120×4.7
= 564watts
c) Energy used = Power consumed × time taken
Energy used = Power × time
Energy used by blow dryer = 1440×20×60
= 1,728,000Joules
Energy used up by vacuum cleaner = 564×46×60
= 564×2760
= 1,556,640Joules
Ratio of the energy used by the blow-dryer in 20 minutes to the energy used by the vacuum cleaner in 46 minutes will be 1,728,000/1,556,640 = 1.11
Well over time the temperature of the water increase causeing its moleclues to move alot which causes it's state change to a gas this is who we have rain.