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3 years ago

11

A wire 0.50 m long carrying a current of 16.0 A is at right angles to a 0.20 T magnetic field. How strong a force acts on the wi

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1 answer:

Svetlanka [38]3 years ago

6 0

I think answer should be 15 please give me brainlest let me know if it’s correct or not okay thanks bye

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In the diagram, above, marker F is pointing to a __________, which are formed when meanders wear away at a narrow point and a po

castortr0y [4]

The answer is <span>oxbow lake</span>

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3 years ago

Read 2 more answers

Think about the process of pulling down the spring and letting it go. For this event, list each form of energy associated with t

Afina-wow [57]

Answer:

gravitational 2.force of gravity

Explanation:

1.it ocours when an object is thrown into the sky. 2.iy ocurs when an object is falling or being pulled from the sky

6 0

2 years ago

Guys No one's answering my question so sad! Once again I'm asking the same question –Here

nexus9112 [7]

For the front glass of the car to get wet, $V_c \geq 10 \ m/s$ .

The given parameters:

<em>Speed of the car, = Vc</em>
<em>Speed of the rain, = 10 m/s</em>

The relative velocity of the car with respect to the falling rain is calculated as;

$V_{C/R} = V_C- V_R$

If the speed of the car equals the speed of the rain, the rain will fall behind the car.
If the speed of the rain is greater than speed of the car, the rain will fall far in front of the car.
If the speed of the car is greater than speed of the rain, the rain will fall on the car.

Thus, for the front glass of the car to get wet, $V_c \geq 10 \ m/s$ .

Learn more about relative velocity here: brainly.com/question/17228388

8 0

3 years ago

What is an advantage of using oil instead of wind to generate electricity?

Anastaziya [24]

A is the only logical answer

3 0

3 years ago

5. If a spring with a 40 N/m spring constant is used to push a 10 kg ball to a speed of 2 m/s,

kolbaska11 [484]

By compressing the spring a distance <em>x</em> (in m), you are storing 1/2 <em>k</em> <em>x</em> ² (in J) of potential energy, which is converted completely into kinetic energy 1/2 <em>m v</em> ², where

• <em>k</em> = 40 N/m = spring constant

• <em>m</em> = 10 kg = mass of the ball

• <em>v</em> = 2 m/s = ball's speed (at the moment the spring returns to its equilibrium point)

So we have

1/2 <em>k</em> <em>x</em> ² = 1/2 <em>m</em> <em>v</em> ²

<em>x</em> = √(<em>m</em>/<em>k</em> <em>v</em> ²) = √((10 kg) / (40 N/m) (2 m/s)²) = 1 m

3 0

3 years ago