Answer:
The probability that their first child will have long fingers is 20%
Explanation:
<u>Available data</u>:
- long fingers are inherited with 80% penetrance
- L represents the dominant allele for short fingers
- l represents the recessive allele for long fingers
Cross) Two people heterozygous for long fingers mate
Ll x Ll
Gametes) 1/2 L 1/2l 1/2L 1/2l
Punnet Square)
L l
L LL Ll
l Ll ll
F1) 25% or 1/4 LL
50% or 1/2 Ll
25% or 1/4 ll
Long fingers are inherited with 80% penetrance, which means that 80% is the proportion of the population that expresses the phenotype long fingers. Hence, the probability that the first child in this cross will have long fingers is:
100% ------- 80%
25% -------- X = 20%
Answer:
The correct answer is 3' UCA 5'
Explanation:
The rule of pairing of base-pair says that A and T base pairs with each other with two hydrogen bonds and G and C base pairs with each other with three hydrogen bonds in DNA. In the case of RNA Uracil comes at the place of thymine that means uracil replaces thymine.
Therefore according to this base-pairing rule the corresponding codon of mRNA transcribes from DNA codon 5' AGT 3' will be 3' UCA 5' as U came in place of A nucleotide, C comes in place of G nucleotide, and A comes in place of T nucleotide.
Therefore the correct answer is 3' UCA 5'.
Scanning Electron Microscope (SEM). Check Google next time lol
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