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3 years ago

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Mathematics

1 answer:

Len [333]3 years ago

7 0

Answer:

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The following formula can be used to find the distance that a person has run. distance = rate · time How far has a person travel

Nataly_w [17]

It is a trick question. multiply 5.5 times 0.75=4.125

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4 years ago

A square field has an area of 479 ft^2. What is the approximate length of a side of the field? Give your answer to the nearest f

jeyben [28]

The answer will be 22 square ft. hope it helps

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3 years ago

Consider a 3×10 grid of points. Suppose that starting at the lower left corner, you can go one step up or one step to the right

astraxan [27]

Answer:

Step-by-step explanation:

Before to get started we are going to imagine a grid with 3 rows and ten columns.

In order to find how many different paths are possible to reach the upper right corner from the lower left corner we have to take in account that every possible route has just 13 moves. 3 right moves and 10 up moves.

Since order does not matter in our paths , we can solve this problem using combination formula.

C(n,r)= $\frac{n!}{r!*(n-r)!}$

Let n=all possible moves

r= number of right or up moves

The number of possible paths can be found by finding how many combinations of right moves or up moves we can have in all possible moves. We will end up with he exact same result.

In this case we will use r as the number of up moves.

C(13,10)= $\frac{13!}{10!(13-10)!} =286$

286 paths are possible!

4 0

3 years ago

A hog producer is feeding soybean meal and corn to his pigs. He needs to know how many pounds he needs to feed of each in order

Mazyrski [523]

Answer:

Feed 1, Soybean meal required = $\dfrac{2000}{3} \text{ lbs.}$

Feed 2, Corn meal required = $\dfrac{4000}{3} \text{ lbs.}$

Step-by-step explanation:

Total feed is 1 ton i.e. 2000 lbs.

Let x be the amount of Feed 1 required.

Feed 1 has $45\%$ of protein.

$\text{Protein in Feed 1 = }x \times \dfrac{45}{100} ..... (1)$

Then, amount of Feed 2 required = $(2000 - x) \text{ lbs.}$

Feed 2 has $15\%$ of protein.

$\text{Protein in Feed 2 = }(2000 - x) \times \dfrac{15}{100} ..... (2)$

As per question, total protein required is $25\%$ of 2000 lbs .

Adding (1) and (2) and putting it equal to total protein required.

$\Rightarrow x \times \dfrac{45}{100} + (2000 - x) \times \dfrac{15}{100} = 2000 \times \dfrac{25}{100}\\\Rightarrow 45x + 30000 - 15x = 50000\\\Rightarrow 30x = 20000\\\Rightarrow x = \dfrac{2000}{3}$