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The greater of two consecutive even integers is eleven more than half the lesser. Determine the integers.

exis [7]

The lesser of two consecutive even integers is 10 more than one-half the greater. Find the integers.
1st: 2x
2nd: 2x+2
-----
EQUATION:
2x =(1/2)(2x+2)+10
2x = x + 11
x = 11
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1st: 2x = 22
2nd: 2x + 2 = 24
===================================

2) The greater of two consecutive even integers is 6 less than the times the lesser

3) Find four consecutive integers such that twice the sum of the two greater integers exceeds three times the first by 91.
1st: x
2nd: x+1
3rd: x+2
4th: x+3
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EQUATION:
2(x+2 + x+3) = 3x + 91
4x + 12 = 3x + 91
x = 79
x+1 = 80
etc.
======================
4) Find a set of four consecutive positive integers such that the greatest integer in the set is twice the least integer in the
I'll leave this to you.

5 0

3 years ago

On a coordinate plane, a shape is plotted with vertices of (3, 1), (0, 4), (3, 7), and (6, 4). what is the area of the shape if

QveST [7]

Let
A (3, 1)
B (0, 4)
C(3, 7)
D (6, 4)

step 1
find the distance AB
d=√[(y2-y1)²+(x2-x1)²]------> dAB=√[(4-1)²+(0-3)²]-----> dAB=√18 cm

step 2
find the distance CD
d=√[(y2-y1)²+(x2-x1)²]------> dCD=√[(4-7)²+(6-3)²]-----> dCD=√18 cm

step 3
find the distance AD
d=√[(y2-y1)²+(x2-x1)²]------> dAD=√[(4-1)²+(6-3)²]-----> dAD=√18 cm

step 4
find the distance BC
d=√[(y2-y1)²+(x2-x1)²]------> dBC=√[(7-4)²+(3-0)²]-----> dBC=√18 cm

step 5
find slope AB and CD
m=(y2-y1)/(x2-x1)
mAB=-1
mCD=-1
AB and CD are parallel and AB=CD

step 6
find slope AD and BC
m=(y2-y1)/(x2-x1)
mAD=1
mBC=1
AD and BC are parallel and AD=BC
and
AB and AD are perpendicular
BC and CD are perpendicular

therefore
the shape is a square wit length side √18 cm

area of a square=b²
b is the length side of a square
area of a square=(√18)²------> 18 cm²

the answer is
18 cm²

see the attached figure

6 0

3 years ago

4/9 - 2/5 give answer in its simpliest form

wlad13 [49]

Answer:

2/45 is your answer

8 0

1 year ago

If an intravenous solution containing 123 mg of a drug substance in each 250-mL bottle is to be administered at the rate of 200

12345 [234]

Answer:

24.39mL of the solution would be given per hour.

Step-by-step explanation:

This problem can be solved by direct rule of three, in which there are a direct relationship between the measures, which means that the rule of three is a cross multiplication.

The first step to solve this problem is to see how many mg of the solution is administered per hour.

Each minute, 200 ug are administered. 1mg has 1000ug, so

1mg - 1000 ug

xmg - 200 ug

$1000x = 200$