The frequency of the third harmonics of the closed pipe is 850 Hz.
<h3>
Third harmonics frequency</h3>
The frequency of the third harmonics or second overtone is determined as follows;
Wavelength, λ = 4L/3
Frequency, F = v/λ
Where;
- v is the velocity of sound in air = 340 m/s
- L is length of the pipe = 0.3 m
Substitute the given parameters and solve for the frequency
F₃ = (3 x 340)/(4 x 0.3)
F₃ = 850 Hz
Thus, the frequency of the third harmonics of the closed pipe is 850 Hz.
Learn more about third harmonics here: brainly.com/question/4290297
Answer:
A: greater than the volume of object B
Explanation:
Based on the dimensions, the volume of object A is ...
(3 cm)(2 cm)(4 cm) = 24 cm³ = 24 mL
If object B displaces 19 mL of water, we presume that is its volume. Since 24 mL is more than 19 mL, we conclude ...
The volume of object A is greater than the volume of object B.
_____
<em>Comment on density</em>
We have presumed that object B is completely submerged. If it is not, then the relative volumes will depend on the densities. If the density of object B is less than about (19/24) g/mL, its volume may very well be larger than that of object A.
As we know that electric field at a point due to a point charge is given by
here we can see that electric field is directly depends on the magnitude of charge
so if we change the magnitude of charge by some factor then electric field will change by same factor
so here as given that charge is doubled
then electric field due to that charge at the same point also get doubled
Answer:
B) 89500 km
Explanation:
speed = distance / time
time= 3h 58 min = 30+58/60= 30.966 h = 31 hrs (approxx)
250= distance / 31
250× 31= distance
distance = 7750 ( approxx)
but none of the given options is 7750 km so we will choose the answer nearest to it,
therefore 89500km is the right answer
I think it's D. Usually, to find the volume of an irregularly shaped object, you put it in water with a labeled beaker to measure how much the water rises. The balance would be used to measure the mass in grams.