Show that in a collision between a heavy particle and an electron the highest speed the electron can receive is 2Mv/(M+mo), wher
e v is the speed of the heavy particle and M and mo are the rest masses of the heavy particle and the electron. Assume non-relativistic particles.
1 answer:
Answer:

Explanation:
- We have to apply the momentums conservation principle. The momentum before the collision is the same at the momentum after the collision.
- If the electron receives the highest speed possible, so the energy is conserved during the collision.
before the collision, the velocity of the heavy particle is v:


After the collision :


So:
(1)
⇒
(2)
in the first equation:

if we replace
in the equation (2):


so:


Finally:

You might be interested in
Larger mass creates a stronger pull
Answer:
1 r = 6.283185 rad
677,762,308.31685 rad
Explanation:
Medicine to a patient. That should be calculated based on weight, strength/dosage and possibly other factors
Answer:
0.037 A
Explanation:
Magnetic field = B = 1.00 e-4 T
Length = L = 0.380 m
Number of turns = 810
B = μ₀ N I / L
⇒ Current = I = B L / μ₀ N = ( 1 e-4) ( 0.380) / (4π × 10⁻⁷)(810)
= 0.037 A = 37.3 mA