Answer:
30%
Explanation:
I don't know how to explain but I learnt this yesterday
Answer:
H_2O + 2CrO_4^2- + 3SO_3^2- -> 3SO_3^2- + 2CrO_2^- + 2OH^-
Explanation:
Reduction half reaction
2H_2O + CrO_4^2- + 3e -> CrO_2^- + 4OH^-
Oxidation half reaction
2OH^- + SO_3^2- -> SO_4^2- + H_2O + 2e
Balanced overall equation
H_2O + 2CrO_4^2- + 3SO_3^2- -> 3SO_3^2- + 2CrO_2^- + 2OH^-
Answer:
ammmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmm yeah i dont know
Explanation:
Cl⁻ + H₂O(g) = HCl(g) + OH⁻
w - it is percent chloride ions in solid sea salt (as a rule 55%)
m - it is the mass of sea salt
m(Cl⁻)=mw/100
m(Cl⁻)/M(Cl)=V(HCl)/V₀
mw/{100M(Cl)}=V(HCl)/V₀
m=100M(Cl)V(HCl)/{wV₀} (<span>the mass of solid sea salt)</span>
V₀=22.4 L/mol
M(Cl)=35.45 g/mol
for example:
V(HCl)= 1.0 L
w=55%
m=100×35.45×1.0/{55×22.4}=2.88 g
