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Fittoniya [83]
2 years ago
6

Students are investigating the differences in open and closed systems. They heated 2 containers of water. They recorded their re

sults in the tables shown.
Two tables.Short description, Two tables.,Long description,
Container 1
Before After Mass of Container and Contents in grams 200 150 Volume of Water in milliliters 100 50
Container 2
Before After Mass of Container and Contents in grams 200 200 Volume of Water in milliliters 100 50
Question
What can the students conclude from the results of their investigation?
Answer options with 4 options
A.
Container 1 is a closed system because a gas was produced. Gases do not have mass.
B.
Container 1 is an open system because a gas was produced. Gases make things lighter.
C.
Container 2 is an open system because the volume changed even though the mass did not change.
D.
Container 2 is a closed system because the mass did not change even though the volume changed.
Chemistry
1 answer:
kow [346]2 years ago
6 0

Container 2 is a closed system because the mass did not change even

though the volume changed.

<h3>What is a Closed system?</h3>

A closed system is the type of system which prohibits the transfer of

matter in and out the system.

In a closed system , the mass of the matter present is always the same

regardless of the changes which occurred which is why option D is the

most appropriate option.

Read more about Closed  system here brainly.com/question/3690180

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An example of basic research is A) the development of new plastics that can be recycled. B) the study of the relationship betwee
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Answer:

C) the study of the composition of the atom.

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5 0
2 years ago
An actacide tablet containing Mg(OH)2 (MM = 58.3g / (mol)) is titrated with a 0.100 M solution of HNO3. The end point is determi
PtichkaEL [24]

Answer:

0.0583g

Explanation:

The equation of the reaction is;

2HNO3(aq) + Mg(OH)2(aq) -------> Mg(NO3)2(aq) + 2H2O(l)

From the question, number of moles of HNO3 reacted= concentration × volume

Concentration of HNO3= 0.100 M

Volume of HNO3 = 20.00mL

Number of moles of HNO3= 0.100 × 20/1000

Number of moles of HNO3 = 2×10^-3 moles

From the reaction equation;

2 moles of HNO3 reacts with 1 mole of Mg(OH)2

2×10^-3 moles reacts with 2×10^-3 moles ×1/2 = 1 ×10^-3 moles of Mg(OH)2

But

n= m/M

Where;

n= number of moles of Mg(OH)2

m= mass of Mg(OH)2

M= molar mass of Mg(OH)2

m= n×M

m= 1×10^-3 moles × 58.3 gmol-1

m = 0.0583g

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