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3 years ago

8

A ball is thrown from a height of 32 meters with an initial downward velocity of 2/ms. The ball's height h (in meters) after t s

econds is given by the following. =h−32−2t5t2 How long after the ball is thrown does it hit the ground?

1 answer:

Bumek [7]3 years ago

6 0

0=65-10t-5t^2

now what you want to do is multiply a and c

-5(t^2+2t-13)

Now just find the zeros

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