Question

A ball is thrown from a height of 32 meters with an initial downward velocity of 2/ms. The ball's height h (in meters) after t seconds is given by the following. =h−32−2t5t2 How long after the ball is thrown does it hit the ground?

Answer 1

0=65-10t-5t^2

now what you want to do is multiply a and c

-5(t^2+2t-13)

Now just find the zeros