A monobromination reaction of an alkane involves an alkane and bromine. The position of the hydrogen atom that will be substituted by the bromine free radical will depend on the order of the alkane. The bromine will attach to the carbon that has the most substituents.
Answer:
D
Explanation:
I believe the answer is D because atoms are always seeking to fill up their outer electron shell/valence shell and want to gain a full octet.
Answer:
Explanation:
Hello,
In this case, since the given 5-M concentration of magnesium chloride is expressed as:
We can notice that one mole of salt contains two moles of chloride ions as the subscript of chlorine is two, in such a way, with the volume of solution we obtain the moles of chloride ions as shown below:
Best regards.
2KMnO4+3Na2SO3+H2O→2MnO2+3Na2SO4+2KOH
In a reaction, the reducing agent is the element or compound that donates electron or the one tht loses electrons. The oxidized species. The opposite is called the oxidizing agent. It is the one who accepts the electrons lost. For this reaction KMnO4 is reduced into MnO2.
Answer:
The answer is C
Explanation:
This is the answer because it is the only way that it is okay to split in half.
