The temperature of the countertop changes by 0.032 °C
The quantity of heat transferred to the countertop is given by
Q = CΔT where Q = quantity of heat transferred to the countertop = 5000 J = 5 kJ, C = heat capacity of the countertop = 158.5 kJ/°C and ΔT = temperature change of the countertop.
Since we require the temperature change of the countertop, we make ΔT subject of the formula.
So, ΔT = Q/C
So, substituting the values of the variables into the equation, we have
ΔT = Q/C
ΔT = 5 kJ/158.5 kJ/°C
ΔT = 0.032 °C
So, the temperature of the countertop changes by 0.032 °C
Learn more about temperature change here:
brainly.com/question/16384350
I believe the correct response is C. They occurred at different rates.
An aqueous solution of potassium sulfate exhibits colligative properties. Colligative properties are properties that depends on the concentration of a substance in a solution. These properties are freezing point depression, vapor pressure lowering, osmotic pressure and boiling point elevation. For this problem we use the concept of freezing point depression since we are given the freezing point of the solution. Freezing point depression is as:
ΔT = -k(f) x m x i
-2.24 - 0 = -1.86 x m x 3
<span>m = 0.4014
Thus, the molality of the solution is 0.4014.</span>
An electron carries a negative power to the atom. in each atom, the amount of protons and electrons are usually evened out so the atom is stable. the electrons of an atom are also found on the outside ring of an atom, unlike protons and neutrons, which are inside the atom. glad to help! :)
